The weak form (19) has been designed as an extension of the standard virtual
work principle to deal with the contact problem with Coulomb friction. Since it is a
genuine weighted residual relationship involving arbitrary (regular) virtual displacements
and multipliers, it can be discretized by means of the finite element method in a simple
way.
The finite element discretization process holds for any isoparametric finite element
on the contact surface. As the weak form already incorporates the contact laws, no local
integration of the frictional equations is required in the numerical solution procedure
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Vietnam Journal of Mechanics, VAST, Vol. 33, No. 4 (2011), pp. 259 – 282
A SIMPLE WEAK FORM FOR CONTACT PROBLEMS
WITH COULOMB FRICTION
Nguyen Huynh Tan Tai1 and Le Van Anh2
1Faculty of Civil Engineering, Thu Dau Mot University, Vietnam
2Faculty of Science, University of Nantes, France
Abstract. This paper proposes a weak form for the contact problem with Coulomb fric-
tion, written as extension of the standard virtual work principle and involving both the
displacements and the multipliers defined on the reference contact surface. The mixed
relationship is shown to be equivalent to the strong form of the initial/boundary value
contact problem, and it can be discretized by means of the finite element method in a
simple way. Typical numerical examples are given to assess the efficiency of the formu-
lation in statics and dynamics.
Key words: Contact, friction, finite element method.
1. INTRODUCTION
Contact problems are of practical significance in mechanics and their solution is
complex because of the nonlinear and non-smooth laws governing the interface response
between the contacting bodies. When large deformations and large slips are involved, the
problem becomes highly nonlinear and robust formulations must be designed with a view
to efficiently solve it.
Over more than three decades, a great number of formulations and solution meth-
ods have been proposed in the literature in order to deal with different kinds of contact
problems encountered, from frictionless contact in linear elastostatics up to frictional con-
tact in large deformation with complex material constitutive and interfacial contact laws,
either in statics or dynamics. A complete review can be found in the books of Wriggers
[1] and Laursen [2], where one can find a great deal of references related to the existing
methods for the treatment of the contact constraints, in particular the classical Lagrange
multiplier, the penalty and the augmented Lagrangian methods.
The augmented Lagrangian methods are the most interesting to date to cope with
the contact inequality constraints inasmuch as it combines the regularizing effect of the
penalty method and the exact satisfaction of the constraints ensured by the Lagrange
multiplier method, without having the ill-conditioning problem inherent to the penalty
method. Kinematically linear problems with frictional contact were solved using the aug-
mented Lagrangian approach by Alart and Curnier [3], Zavarise, Wriggers and Schrefler
[4]. Large deformation contact without friction was also successfully addressed by the same
260 Nguyen Huynh Tan Tai, Le Van Anh
method in the early work of Glowinski and Le Tallec [5] considering a plane rigid obstacle,
in Heegard and Curnier’s paper [6] considering contact between two elastic bodies, and
later in Zavarise and Wriggers [7]. The solution of large deformation frictional contact
problems between deformable bodies was accomplished by Simo and Laursen [8, 9] in-
cluding the algorithmic symmetrization of the contact tangent stiffness matrix, Wriggers
[10], Pietrzak and Curnier [11, 12] and more recently by Feng, Peyraut and Labed [13] for
Blatz-Ko hyperelastic bodies, and Mijar and Arora [14]. All previous works considered the
Coulomb friction model or an extension of it to incorporate micro-mechanical effects for
instance.
This paper proposes a simple formulation for the contact problem with Coulomb
friction, which is close to Curnier et al’s augmented Lagrangian formulations [11, 12]. First,
the basic equations and inequalities governing the strong form of the initial/boundary
value contact problem are formulated in Section 2. Then, a new weak form - similar to
the virtual work principle - is proposed in Section 3 and it is shown to be equivalent to
the strong form of the contact problem. The main characteristics of the weak form is that
it contains the inequality constraints specific to contact laws, so that the contact laws are
automatically satisfied regardless of the constitutive laws of the contacting bodies and no
local integration is needed at the contact surface level. The semi-discretization in space
of the weak form by means of the finite element method is conducted in Section 4, which
leads one to solve a coupled nonlinear semi - discrete equation system in two unknowns:
the nodal displacements and the nodal multipliers. Eventually, some numerical examples
in quasi - statics and dynamics assessing the efficiency of the proposed formulation are
presented in Section 5.
2. STRONG FORM OF THE CONTACT PROBLEM
Consider two bodies whose positions at any time are represented by some regions
in a three - dimensional Euclidean affine space. The position at any time of any particle
belonging to the bodies is represented by a point in this space. As usually done, a fixed
origin being chosen, any point as well as the associated position vector will be identified
to a three-component vector in R3. We shall describe the mechanical problem using a
Lagrangian description. The reference configuration of the two bodies are represented by
the regions Ω
(1)
o and Ω
(2)
o in R3. Let us assume that in the time interval [O, T ] of interest,
the two bodies may come into contact with each other through the motions denoted φ(1)
and φ(2)
∀i ∈ {1, 2}, ∀t ∈ [O, T ], φ(i)(., t) : Ω(i)o 3 X
(i) 7→ x(i) = φ(i)(X(i), t) (1)
where X(i) and x(i) are the reference and current positions of any particle of body i,
respectively. The displacement field in body i is defined as U(i) = x(i) −X(i).
The strong form of the problem is expressed by the local equations summarized
below, which must be satisfied at any time t ∈ [O, T ] and at any point X(i) ∈ Ω
(i)
o ,
i ∈ {1, 2}. The linear momentum balance equation can be written for each body i via
divΠ(i) + ρ(i)o f
(i) = ρ(i)o U¨
(i)
(2)
A simple weak form for contact problems with Coulomb friction 261
where Π(i) is the first Piola-Kirchhoff stress tensor, ρ
(i)
o is the reference density of body
i and f(i) the prescribed body force per unit mass. The constitutive relationships relating
stress to strain are left unspecified until the numerical examples are considered. This
means that the weighted residual relationship proposed hereafter holds for all constitutive
materials, as is the case with the standard virtual work principle.
The reference boundary S
(i)
o of body i is partitioned into three non-overlapping
and pairwise disjoint parts denoted S
(i)
oU , S
(i)
oT and S
(i)
oc , where S
(i)
oU and S
(i)
oT are the parts
where the displacement and the tractions are prescribed, respectively, and S
(i)
oc is the part
where contact potentially takes place between the two bodies during some portion of the
time interval [O, T ]. The boundary conditions on S
(i)
oU and S
(i)
oT on each body i can be
summarized as
U(i) = U¯
(i)
in S
(i)
oU , Π
(i)N(i) = T¯
(i)
in S
(i)
oT (3)
where U¯
(i)
, T¯
(i)
are the prescribed displacement and nominal traction, respectively, N(i)
the unit outward normal at point X(i) to surface S
(i)
o . The boundary conditions on the
contact surface will be presented in detail in Section 2.2. The initial conditions for body i
are
∀X(i) ∈ Ω(i)o , U
(i)(X(i), 0) = 0, U˙
(i)
(X(i), 0) = V¯
(i)
0 (X
(i)) (4)
where V¯
(i)
0 is the prescribed initial velocity field for body i.
2.1. Contact kinematics
Let us denote the spatial counterparts of Ω
(i)
o , S
(i)
o , S
(i)
oU , S
(i)
oT and S
(i)
oc by Ω(i), S(i),
S
(i)
U , S
(i)
T and S
(i)
c , respectively, e.g., S
(i)
c = φ
(i)(S
(i)
oc , t). In order to describe the relative
motion of the two bodies, we arbitrarily choose one body (the target), say body 2, as the
reference and to evaluate the proximity of the other (the contactor), thus body 1, with
respect to it.
It is assumed that the reference surface S
(i)
oc , i = 1 or 2, is parametrized by the
mapping θ(i) and the current surface S
(i)
c at time t by the mapping ψ
(i)(., t)=φ(i)(., t)◦θ(i):
A region of R2 → S(i)oc ⊂ R
3 → S(i)c ⊂ R
3
ξ(i) = (ξ(i)1, ξ(i)2) 7→ X(i) = θ(i)(ξ(i)) 7→ x(i) = φ(i)(X(i), t) = ψ(i)(ξ(i), t)
(5)
Consider a particular point x ∈ S
(1)
c and define the opposite point y ∈ S
(2)
c as the
closest point to x in the Euclidean sense (Fig. 1):
y = arg min
x(2)∈S
(2)
c
‖x− x(2)‖ (6)
As may be seen, the notation x(i), i ∈ {1, 2}, in (5) designates any point on S
(i)
c ,
whereas the notation x designates a particular point of interest on S
(1)
c and y the opposite
point of x on S
(2)
c defined by (6). Considering the point X ∈ S
(1)
oc related to the point x
considered by x = φ(1)(X, t), then the point Y ∈ S
(2)
oc related to point y by y = φ
(2)(Y, t)
262 Nguyen Huynh Tan Tai, Le Van Anh
Fig. 1. Contact kinematics
satisfies
Y = arg min
X
(2)
∈S
(2)
oc
‖φ(1)(X, t)−φ(2)(X(2), t)‖ (7)
A point Y thus being associated to point X, the proximity g is defined by
g = −ν(x− y) = −ν(φ(1)(X, t)− φ(2)(Y, t)) (8)
where ν is the normal at point y. The sign convention chosen in (8) implies that the prox-
imity g is positive when there is interpenetration and negative when there is a gap between
the two bodies. Moreover, the inverse image of X (resp. Y) under the parametrization θ(1)
(resp. θ(2)) will be denoted ξ (resp. η). By making x(2) = ψ(2)(ξ(2), t) in (6), one finds
that η is characterized by
η = argmin
ξ(2)
‖x− ψ(2)(ξ(2), t)‖ (9)
For notational conveniences, the dependencies on φ(1), φ(2) and ψ(2) will be omitted
in the material kinematics variables and only the dependency on (X, t) will be shown. Thus,
for instance, one writes η = η(X, t) and g = g(X, t). Assuming that all the mappings
introduced are smooth enough, let us define the natural basis (a1, a2) at point y ∈ S
(2)
c as
a1 =
∂ψ(2)
∂ξ(2)1
(η(X, t), t), a2 =
∂ψ(2)
∂ξ(2)2
(η(X, t), t) (10)
The surface S
(2)
c is parametrized conveniently so that the normal n = a1×a2/‖a1×
a2‖ at y to S
(2)
c is directed toward the contactor. Use will also be made of the dual basis
(a1, a2) lying in the tangent plane of the current target surface as follows
∀α ∈ {1, 2}, aα = aαβaβ (11)
where implicit summation from 1 to 2 is assumed over repeated Greek indices and the
2 × 2 matrix [aαβ] is the inverse of matrix [aαβ] = [aα.aβ]. Eventually, the contact laws
A simple weak form for contact problems with Coulomb friction 263
with friction involve the following objective relative velocity at point X and time t [15, 16]
V = V(1)(X, t)−V(2)(Y(X, t), t) + gν˙ = −g˙ν + η˙αaα (12)
where V(1)(X, t) and V(2)(Y, t) are the velocities of the particles X and Y(X, t), respec-
tively. The rates g˙ and η˙α are given by [1, 2]:
g˙ = −
[
V(1)(X, t)−V(2) (Y(X, t), t)
]
ν
η˙α = a¯αβaβ [V
(1)(X, t)−V(2)(Y(X, t), t)]− ga¯αβνV
(2)
,β (η, t)
(13)
where matrix [a¯αβ] is the inverse of matrix [a¯αβ], with a¯αβ = aαβ + gκαβ, καβ = νψ,
(2)
αβ is
the curvature of the surface ψ(2) at η. On the basis of (12) one can define the slip velocity
or the relative tangential velocity VT as the projection of V into the tangent plane at y
to S
(2)
oc :
VT = (I− ν ⊗ ν).V = η˙
αaα (14)
It should be noted that the slip rate VT associated to the material point X ∈ S
(1)
oc
is resolved in terms of the spatial basis (a1, a2) at point y ∈ S
(2)
c . As done with other
kinematical quantities, use will be made of the abbreviated notations V = V(X, t) and
VT = VT (X, t), omitting the dependencies on motions φ
(1), φ(2).
2.2. Contact laws
Let T(X, t) = Π(1).N be the nominal Piola-Kirchhoff traction vector at point X ∈
S
(1)
oc (N is the normal vector at X to S
(1)
oc ). It is resolved in terms of the spatial basis at
y ∈ S
(2)
c as follows
T(X, t) = TN(X, t)ν −TT (X, t) = TN(X, t)ν − TTαa
α (15)
The normal contact law reads
∀t ∈ [O, T ], ∀X ∈ S
(1)
oc , g(X, t) ≤ 0
{
if g(X, t) < 0, then TN(X, t) = 0
if g(X, t) = 0, then TN(X, t) ≥ 0
(16)
The tangential contact response is modeled by the Coulomb friction law:
∀t ∈ [O, T ], ∀X ∈ S(1)oc ,
(a) g(X, t) < 0⇒ TT (X, t) = 0 (no relationship for VT (X, t))
(b) g(X, t) = 0⇒ ‖TT (X, t)‖ ≤ µTN(X, t)
where
{
if ‖TT ‖ < µTN , then VT = 0 (stick)
if ‖TT ‖ = µTN , then VT ×TT = 0,VT .TT ≥ 0 (slip)
(17)
where µ > 0 is the coefficient of friction. It can be verified that the contact laws (16)-(17)
are objective.
264 Nguyen Huynh Tan Tai, Le Van Anh
3. WEAK FORM OF THE CONTACT PROBLEM
In this section, the strong form of the contact problem - described by equations
(1)-(2), the constitutive law, the boundary conditions (3), the contact laws (16)-(17) and
the initial conditions (4) - will be converted into an equivalent weak form which is more
convenient for the finite element implementation.
Our approach is inspired by the augmented Lagrangian formulation of Pietrzak and
Curnier [12] and results in a weighted residual relationship which involves the displacement
fields U(i), i ∈ {1, 2}, defined in Ω
(i)
o , and the multiplier field λN(X) and λT (X) = λTαa
α
defined on S
(1)
oc . Accordingly, the weighting functions are the virtual displacements U
(1)∗,
U(2)∗, and the virtual multipliers λ∗N , λ
∗
T = λ
∗
Tαa
α. One needs the following preliminary
result:
Proposition 1. Two positive constants N , T being chosen, the contact laws (16)-
(17) are equivalent to the following equalities on S
(1)
oc :
λN = 〈λN + N g〉
λT =
(
1− 〈1−
µ〈λN + Ng〉
‖λT + TVT‖
〉
)
(λT + TVT )
(18)
where 〈.〉 is the Macauley bracket: 〈a〉 = a if a ≥ 0, = 0 if a < 0.
The proof is given in [17, 18]. Using the equalities (18) then enables one to formulate
the weak form for the contact problem as follows:
Proposition 2.
(i) The solution fields of the strong problem – namely U(1), U(2) in Ω
(1)
o ,Ω
(2)
o and
TN , TT , VT on S
(1)
oc - satisfy the following relationship, provided one makes λN = TN and
λT = TT : ∀t ∈ [O, T ], ∀U
(1)∗, ∀U(2)∗, ∀λ∗N , ∀λ
∗
T 1, ∀λ
∗
T 2,
2∑
i=1
{
−
∫
Ω
(i)
o
Π
(i)T : ∇
X
(i)U
(i)∗dΩo +
∫
Ω
(i)
o
ρ(i)o f
(i)
U
(i)∗dΩo +
∫
S
(i)
oU
∪S
(i)
oT
T
(i)
U
(i)∗dSo
}
+
∫
S
(1)
oc
[
〈λˆN〉ν −
(
1− 〈1 −
µ〈λˆN 〉
‖λˆT ‖
〉
)
(λˆT )
](
U
(1)∗(X)−U(2)∗(Y(X))
)
dSo
+
∫
S
(1)
oc
{
(λN − 〈λˆN 〉)
λ∗
N
N
+
[
λT −
(
1− 〈1−
µ〈λˆN 〉
‖λˆT ‖
〉
)
λˆT
]
λ∗
T
T
}
dSo
=
2∑
i=1
∫
Ω
(i)
o
ρ(i)o U¨
(i)
U
(i)∗dΩo
(19)
where λˆN ≡ λN + Ng, λˆT ≡ λT + TVT , ∇X(i)U
(i)∗ is the gradient tensor of U(i)∗ with
respect to variables X(i), and 〈1 −
µ〈λˆN〉
‖λˆT ‖
〉 must be replaced by 0 at any point on S
(1)
oc
where λˆT = 0.
(ii) Conversely, the contact surfaces S
(1)
c and S
(2)
c being parametrized by ξ 7→ x ∈
S
(1)
c and η 7→ y ∈ S
(2)
c , it is assumed that there is a bijective (or piecewise bijective)
A simple weak form for contact problems with Coulomb friction 265
mapping S
(1)
c 3 x 7→ y ∈ S
(2)
c between them. Then, relation (19) implies at any time
t ∈ [O, T ] the following local equations:
(1) The momentum balance equation (2) for the two bodies 1 and 2.
(2) Relation (3b) on the boundary portion S
(i)
o \S
(i)
oc = S
(i)
oT ∪ S
(i)
oU : Π
(i)N(i) = T(i).
(3) The following equalities between the components of the nominal traction vectors
and the multipliers on the contactor surface S
(1)
oc
∀X ∈ S(1)oc , T
(1) = Π(1)N(1) = λNν − λT ⇔ TN = λN and TT = λT (20)
(4) The normal and tangential contact laws (16) and (17).
(5) The following relationship which expresses the equilibrium of the traction vectors
at the contact interface
∀X ∈ S(1)oc ,T
(2)(Y)dS(2)oc =−(λNν − λT )
‖X,ξ1 ×X,ξ2 ‖
‖Y,η1 ×Y,η2 ‖
Dξ
Dη
dS(2)oc =−T
(1)(X)dS(1)oc (21)
where point Y = Y(X, t) ∈ S
(2)
oc corresponds to point X through the above-mentioned
bijection, dS
(1)
oc is a differential reference area in S
(1)
oc and dS
(2)
oc its counterpart in S
(2)
oc
related to dS
(1)
oc .
4. FINITE ELEMENT DISCRETIZATION AND SEMI-DISCRETE
EQUATION SYSTEM
The spatial discretization of the weighted residual relationship (19) by means of the
finite element method will be detailed for the terms pertaining to contact in equality (19)
only, since the other terms can be discretized in a standard way. Let the contactor surface
S
(1)
oc (resp. the target surface S
(2)
oc ) be subdivided into isoparametric finite elements e(1)
(resp. e(2)) (the superscripts (1) and (2) are used throughout to remind of surfaces S
(1)
oc
and S
(2)
oc ). One obtains the following semi-discrete coupled equation system
[M]{U¨}+ {Ψ(U)} = {Φ}+ {Φcontact(U,Λ)}
{RΛ(U,Λ)} = {0}
(22)
The unknowns in (22) are the nodal displacement vector {U} =
{
{U(1)}
{U(2)}
}
in the
two bodies 1 and 2, and the multiplier vector {Λ} on the reference contact surface S
(1)
oc .
[M] is the mass matrix, {Ψ(U)} the internal force vector resulting from the strain work
in the bodies, {Φ} the external force vector excluding contact force.
The contact force vector {Φcontact(U,Λ)} and the residual vector {RΛ(U,Λ)} for
the multipliers are the assemblies of the element vectors {Φcontact}ej(ξ) and {RΛ}ej(ξ),
where j(ξ) is the area jacobian times the weight corresponding to the parent coordinates
ξ = (ξ1, ξ2) ∈ R
2 of quadrature point X ∈ e(1), see Fig. 1
j(ξ) = ‖X,ξ1 (ξ)×X,ξ2 (ξ)‖.(weight at location ξ) (23)
266 Nguyen Huynh Tan Tai, Le Van Anh
and
{Φcontact}
e =
[N (1)(ξ)]e
(1)
T
(
〈λˆN〉{ν} −
(
1− 〈1−
µ〈λˆN〉
‖λˆT ‖
〉
)
{λˆT }
)
−[N (2)(η)]e
(2)
T
(
〈λˆN 〉{ν} −
(
1− 〈1−
µ〈λˆN 〉
‖λˆT ‖
〉
)
{λˆT }
)
(24)
{RΛ}
e = [N (1)(ξ)]e
(1)
T
(
1
N
(
〈λˆN 〉 − λN
)
{ν}+
1
T
{
λT −
(
1− 〈1−
µ〈λˆN 〉
‖λˆT ‖
〉
)
λˆT
})
(25)
Note that
1−
〈
1−
µ〈λˆN〉
‖λˆT ‖
〉
=
0 if λˆN < 0 (algorithmic gap)
µλˆN
‖λˆT‖
if λˆN ≥ 0 and ‖λˆT ‖ ≥ µλˆN (algorithmic contact with slip)
1 if λˆN ≥ 0 and ‖λˆT ‖ < µλˆN (algorithmic contact with stick)
(26)
In (26), use has been made of the adjective "algorithmic" in order to emphasize
the difference with the "real" situation. For instance, the "algorithmic gap" case means
λˆN = λN + Ng < 0, in contrast with the real "gap" case which merely means g < 0; and
the "algorithmic slip" case means ‖λˆT ‖ ≥ µλˆN , as opposed to the ‘slip’ case which means
‖λT ‖ = µλN .
The nonlinear semi-discrete equations (22) will be solved as a whole using the stan-
dard full Newton-Raphson method to simultaneously obtain the nodal displacements and
the multipliers, as was done in [6, 12, 7].
• The slip velocity VT = η˙αaα defined in (14) and involved in (24)-(25) has to be
computed here by means of an adequate temporally discrete expression. For this purpose,
let us first note that Propositions 1 and 2 remain valid if VT is replaced with VT∆t,
where ∆t is an arbitrary finite time interval. The quantity VT∆t having the dimension of
a length will be referred to as the slip, its use instead of the slip velocity is more consistent
in the numerical context because the penalty parameters N and T involved in the weak
form then have the same dimension of a force by unit volume, i.e. the same SI units of
N/m3. Let us now look at a typical iteration of the current time step n and introduce some
new notations as summarized in Fig. 2. For the sake of brevity, any quantity computed at
the current step n will not be indexed by n, whereas any quantity related to the previous
step will be distinguished by subscript n − 1. Consider two times t and tn−1, which are
respectively the current time corresponding to the current iteration of the current step n
and the time corresponding to the previous step (n−1). Given a particle on the contactor
surface S
(1)
c with reference position X, its position at time tn−1 is xn−1 = φ
(1)(X, tn−1)
and its current position is x = φ(1)(X, t). We denote the following quantities related to
time tn−1:
yn−1 the projection of xn−1 on the target surface S
(2)
c (tn−1) at time tn−1,
Yn−1 and ηn−1 the inverse images of yn−1 under the chain of parametrizations (5).
A simple weak form for contact problems with Coulomb friction 267
Fig. 2. Illustration of the slip VT∆t
It should be emphasized that (i) y and yn−1 are not the respective positions at
times t and tn−1 of a same particle in body 2 and (ii) the current position of the particle
Yn−1 is φ
(2)(Yn−1, t), in general distinct from y = φ
(2)(Y, t).
With these notations in hand, using the chain of parametrizations (5), which gives
y = ψ(2)(η, t) and ψ(2)(ηn−1, t) = Φ
(2)(Yn−1, t), and applying the backward Euler in-
tegration scheme with time step ∆t = t − tn−1 leads to the following expression for the
slip
VT∆t = y−Φ
(2)(Yn−1, t) (27)
• The tangent stiffness matrix related to contact, required for the Newton-Raphson
solution of the coupled equation system (22), is the square matrix:
[Kcontact] =
[
[KUU ] [KUΛ]
[KΛU ] [KΛΛ]
]
(28)
obtained by assembling the element contact stiffnesses [Kcontact]
e:
[Kcontact]
e =
[
[KUU ]
e [KUΛ]
e
[KΛU ]
e [KΛΛ]
e
]
(29)
These matrices are rectangular and given in [19].
5. NUMERICAL EXAMPLES
This section presents the numerical examples which are carried out on the basis of
the previous finite element formulation in order to assess the efficiency of the proposed
formulation. All numerical results presented here have been obtained by a home made
finite element code.
268 Nguyen Huynh Tan Tai, Le Van Anh
5.1. Rolling disk
This example involves quasi-static finite displacements and rotations of a disk rolling
between two rigid planes. One of the interesting features of this example is that it allows to
check the accuracy of the discrete expression (27) for the slip rate VT (or the slip VT∆t),
which is the most essential ingredients in the contact kinematics with friction.
Consider an elastic cylinder with radius R = 1m compressed between two rigid
parallel plates. The problem is solved assuming that the cylinder is made of an isotropic
hyperelastic Saint-Venant Kirchhoff material characterized by the strain energy function
in terms of the Green strain E
w(E) =
1
2
λ(trE)2 + µ¯tr(E2) (30)
where the Lamé constants λ, µ¯ are related to Young’s modulus E and Poisson’s ratio ν by
the same relations as in linear elasticity
λ = Eν/(1+ ν)/(1− 2ν) µ¯ = E/2/(1+ ν) (31)
Here, one takes E = 2.1011N/m2 et ν = 0.3. Friction takes place in the contact
between the bodies with the friction coefficient µ = 0.1, a value high enough to ensure the
rolling without slip. The lower plate is at rest, while the upper is submitted to a prescribed
horizontal translation parallel to the x-axis which makes the disk roll, Fig. 3-a.
x
y
-2 -1 0 1 2 3 4
-1
0
1
2
3
4
5
Elastic Cylinder
Fixed plate
Rigid plate
Prescribed y-displacement
x-displacement
Prescribed
(a)
R
x
y
-2 -1 0 1 2 3 4
-1
0
1
2
3
4
5
(b)
Fig. 3. Reference configuration of the rolling disk problem
• Analytical solution.
The problem is solved in plane strain. Before prescribing the horizontal movement,
the upper plate is slightly lowered in the y-direction in such a way that it comes into
contact with the disk without crushing it much. Thus, the deformation of the disk is small
and the following analytical solution from rigid bodies mechanics is acceptable: if there is
no slip, the displacement in x of the disk center is equal to half that of the upper plate.
A simple weak form for contact problems with Coulomb friction 269
For instance, when the upper plate is translated by piR, the disk rotates by a quarter and
the disk center moves by piR/2.
• Numerical results.
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
Fig. 4. Initial position and positions at increments 20, 40, 60, 80, 100, respectively.
The plates are discretized using one Q8 element
270 Nguyen Huynh Tan Tai, Le Van Anh
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
x
y
-2 0 2 4 6
0
2
4
6
Fig. 5. Initial position and positions at increments 20, 40, 60, 80, 100. The plates
are discretized in 12 Q8 elements
The disk is chosen as the contactor and the plates as the targets. The numerical
computations are carried out using two meshes: (i) in the first one, each rigid plate is
discretized in one single eight-node (Q8) element, and the disk in 148 six-node triangle
elements and 333 nodes. (ii) in the second mesh, the plates are discretized in more elements,
A simple weak form for contact problems with Coulomb friction 271
12 Q8 elements, whereas the mesh of the disk remains the same as before, Fig. 3-b. In
order to prevent the rigid body movement of the disk in the y-direction, a small initial
penetration is prescribed at the beginning of the computations. The penalty coefficients
are N = 1.10
10N/m3 and T = 1.10
9N/m3.
The computations are performed in 100 increments, in the last increment the pre-
scribed displacement of the upper plate is Ux = 100× 0.0314 = 3.14m. The convergence
is achieved in 4 iterations in average.
The results obtained with the two meshes are identical to the 8-th digit. This agree-
ment is not so obvious since the projection points y and Yn−1 in (27), in the case of the
finer mesh, often belong to two distinct elements of the target surface, and yet the discrete
expression (27) gives the same result as with the coarse mesh.
Fig. 4 and Fig. 5 show the disk positions at increments 20, 40, 60, 80 and 100.
As can be predicted, the displacement of the upper plate is found to be twice that of
the disk center, as shown in Fig. 6. Table 1 gives the disk rotation values as a function of
the increments, which virtually coincide with the theoretical values since the error is about
0.02% after a quarter of a revolution. These results fully validate the discrete expression
(27).
Increments
D
is
p
la
ce
m
en
t
(m
)
0 20 40 60 80 100
0
0.5
1
1.5
2
2.5
3
3.5
Fig. 6. Displacements as a function of increments : •: horizontal displacement of
the upper plate; ◦: horizontal displacement of the disk center
Table 1. Disk rotation θ
Increment Computed θ(rad) Theoretical θ(rad) Error (%)
20 3.141664E− 01 3.141593E− 01 0.002
40 6.281763E− 01 6.283185E− 01 -0.023
60 9.422779E− 01 9.424778E− 01 -0.021
80 1.256446E+ 00 1.256637E+ 00 -0.015
100 1.570471E+ 00 1.570796E+ 00 -0.021
272 Nguyen Huynh Tan Tai, Le Van Anh
5.2. Interference fit problem
This example deals with a cylinder which is forced into a tapered hole in a deformable
block through application of a prescribed displacement on its top, Fig. 7. This example is
interesting in that both bodies are deformable and may undergo significant plastic strains.
The geometry is the same as in [2]. In the reference configuration, the cylinder has a radius
of 4cm and a length of 30cm. The outer surface of the block is cylindrical, 30cm in radius
and 50cm in length. The tapered hole is the union of a truncated cone (large radius = 4cm,
small radius = 3.5cm, length = 15cm) and a cylindrical part (radius = 3.5cm), so that
the wall angle of the conical part is 1.9◦.
50 cm
30 cm
30 cm
3.5 cm
4 cm
15 cm
Fig. 7. Interference fit problem
Both bodies are made of an elastoplastic material with a linear isotropic hardening.
The elastoplastic formulation and the material data are the same as in [11] : Young’s
modulus E = 100000MPa, Poisson’s ratio ν = 0.3, yield stress σ0 = 300MPa and hard-
ening modulus H = 3560MPa. In the numerical computations, the cylinder is taken as
the contactor and the block as the target.
The problem is modelled in axisymmetry. The whole mesh contains 120 8-node
quadrilaterals (Q8) and 430 nodes. The 10 elements on the contact surface which is the
outer surface of the cylinder are 3-node line elements. Roller boundary conditions are
assumed on the outer and lower surfaces of the block.
The numerical quadrature is made using 3×3 Gauss points in Q8 elements, 7 Gauss
points in the line elements belonging to the contact surface. Computations are performed
without or with friction (µ = 0.2). The penalty parameters are N = 10
11, T = 5.10
10.
The axial prescribed displacement is controlled via the arc length method, with the
arc length regularly incremented by factor 1.05, until the top of the cylinder is moved
through a distance equal to the original cylinder length. The convergence tolerances are
A simple weak form for contact problems with Coulomb friction 273
10−6 for the force residual {R}, the arc-length residual as well as the multiplier residual
{RΛ}.
Without friction, the computation is achieved in 58 steps and the convergence re-
quires 4-5 iterations in average. With friction, the computation is achieved in 301 steps
and the convergence requires 5-6 iterations in average. Fig. 8 shows the deformed configu-
(a) No friction (b) Friction, µ=0.2
Fig. 8. Deformed configurations for the interference fit problem: (a) No friction,
(b) Friction µ = 0.2
rations at the last step without or with friction, Fig. 9 the contours of the effective plastic
strain and Fig. 10 the contact stresses exerted on the cylinder.
0.21
0.19
0.17
0.15
0.13
0.11
0.08
0.06
0.04
0.02
Effective
plastic strain
(a)
0.42
0.38
0.34
0.30
0.25
0.21
0.17
0.13
0.08
0.04
(b)
Effective
plastic strain
Fig. 9. Effective plastic strain in the interference fit problem: (a) No friction, (b)
Friction µ = 0.2
As expected, without friction the cylinder penetrates further into the block than
with friction. Fig. 8b shows that the friction induces larger strains at the upper base of
the cylinder as well as an overflow of the block material surrounding the hole. In the
274 Nguyen Huynh Tan Tai, Le Van Anh
(b) (b)
Fig. 10. Contact stresses on the cylinder for the interference fit problem: (a) No
friction, (b) Friction µ = 0.2
frictionless case, the effective plastic strain in the cylinder reaches its highest value (21%)
at the top, whereas in the frictional case its maximal value is twofold (42%) near the
end of the cylinder and the spread of the plastic region in the block is more significant.
The effective plastic strain in the block is smaller than in the cylinder and concentrated
around the contact interface. In accordance with the extent of the plasticity observed, Fig.
10 shows that the contact stresses are more significant in the presence of friction. It is
found that the cylinder volume remains almost unchanged (maximal change at the last
step less than 0.7%, either with or without friction). This may be due to the fact that
the wall angle is small (1.9◦) and the block itself is deformable, with the result that the
contact stresses are relieved.
Fig. 11 plots the thrust force F versus the displacementW of the top of the cylinder,
|W| (m)
F
(N
)
0 0.1 0.2 0.3
0
5E+06
1E+07
1.5E+07
2E+07
2.5E+07
Friction, µ=0.2
No friction
Fig. 11. Axial force F versus top displacement W for the interference fit problem.
Not all the steps are shown for clarity
A simple weak form for contact problems with Coulomb friction 275
in frictional and frictionless cases. Given a displacement of the cylinder top, the thrust
force is always higher in frictional than in frictionless case. When the cylinder is completely
pushed into the hole, force F in the frictional case is more than 20 times as big as in the
frictionless case, this ratio agrees well with [2]. Without friction, force F is practically
constant after the prescribed displacement reaches about half the reference length of the
cylinder (|W | ≈ 15cm), this result is in good agreement with those reported in [11, 2].
5.3. Disk projected into a wedge
Consider the dynamical interaction between an elastic disk and a wedge bounded by
two rigid walls, Fig. 12. This example is based on Wriggers et al’s study [20] related to a
2D ring and on Magnain’s [21] related to a 2D disk. Here, the disk is modeled in 3D, with
radius 0.1m and thickness 0.02m. The rigid obstacle is defined in plane xz by the four
vertex co-ordinates (in m): A(0.05,-0.305), B(0.15,-0.305), C(0.15,0.095), D(0.13,0.095).
With these dimensions, the half-angle of the wedge is 90◦ − 78.32◦ = 11.68◦.
Y
X
Z
V
0
(a)
Rigid wedge
Y X
Z
78.32°
(b)
0.1m
R=0
.1m
V
0
A B
D C
Fig. 12. Impact of a disk on a wedge: a) 3D view, b) front view
The disk is made of a Saint-Venant Kirchhoff material with E = 5.107N/m2, ν = 0.4
and ρ0 = 700kg/m
3. Before the impact, it is projected in uniform translation along the
opposite direction to z at the velocity V0 = 30m/s. The coefficient of friction between the
disk and the walls is either µ = 0 or µ = 0.4. The disk is chosen as the contactor and
the walls as the target. The penalty parameters are N = 10
11N/m3 and T = 10
9N/m3.
There is no gravity.
In order to check the precision of the numerical computations, the disk and both
walls are discretized without taking into account the symmetry with respect to the central
plane, and the finite element program should provide itself symmetrical results. The disk
contains 88 twenty-node brick elements and 8 fifteen-node prismatic elements. Each wall
is discretized with only one brick element.
The time stepping is carried out using the Moreau scheme with parameters θ = ξ =
1
2
, time step ∆t = 10−4s, and the whole computation takes 130 steps. The convergence
necessitates 3-5 iterations in average without friction and more iterations - 4-7 in average
- in the case of friction.
276 Nguyen Huynh Tan Tai, Le Van Anh
Y X
Z
t=0.000s
Y X
Z
t=0.001s
Y X
Z
t=0.002s
Y X
Z
t=0.003s
Y X
Z
t=0.004s
Y X
Z
t=0.005s
Y X
Z
t=0.006s
Y X
Z
t=0.007s
Y X
Z
t=0.008s
Y X
Z
t=0.009s
Y X
Z
t=0.010s
Y X
Z
t=0.011s
Y X
Z
t=0.012s
Y X
Z
t=0.013s
Fig. 13. Impact of a disk on a wedge. Deformed configurations through the process
- Frictionless case
A simple weak form for contact problems with Coulomb friction 277
• Verification of the inequality g ≤ 0
The numerical results show that the inequality g ≤ 0 is satisfied with high precision
at nodes in contact and at any time: in the increments where contact occurs, the maximum
proximity g over all the contacting nodes is found to be about 10−4m, i.e. 0.1% of the disk
radius.
• Movement of the disk
Fig. 13 displays the disk configurations in the frictionless case. The contact takes
place during about 0.09s, between times t = 0.0016s and t = 0.0106s. The disk plunges
into the wedge and rebounds back, leaving the wall for good after time t > 0.016.
Fig. 14 and Fig. 15 representing the position of the disk center as a function of time
t (s)
U
z
(m
)
0 0.002 0.004 0.006 0.008 0.01 0.012 0.014
-0.1
-0.05
0
0.05
no friction
friction, µ=0.4
Fig. 14. Impact of a disk on a
wedge. The disk center displace-
ment versus time
t (s)
V
z
(m
/s
)
0.002 0.004 0.006 0.008 0.01 0.012 0.014
-30
-20
-10
0
10
20
30
40
Fig. 15. The disk center velocity
versus time in the frictionless
case
shows that the disk center stops at t = 0.006s approximately (the middle of the contact
interval), and then goes back at the average velocity of 30m/s, which is precisely opposite
to the incident velocity. Comparing Fig. 14 with Fig. 19 hereafter giving the kinetic energy,
one finds that the whole disk comes to a standstill at time t = 0.006s when the disk center
reaches the lowest level.
Fig. 16 displays the disk configurations in the frictional case, µ = 0.4. This time,
the disk does not go so far as in the frictionless case and at about time t = 0.0045s when
the disk center is at lowest level, the whole disk comes to a standstill. Afterwards, the
disk rebounds a little before its vibration is stopped by the strong friction and the disk is
finally stuck in the wedge: Fig. 14 and Fig. 20 show that the disk is almost at rest after
tc = 0.008s. All these results are in good accordance with those reported in [20] and [21].
A closer examination of the numerical results shows that once the disk is stuck in
the wedge, it keeps vibrating slightly. However, the vibrations diminish rapidly due to
278 Nguyen Huynh Tan Tai, Le Van Anh
Y X
Z
t=0.000s
Y X
Z
t=0.001s
Y X
Z
t=0.002s
Y X
Z
t=0.003s
Y X
Z
t=0.004s
Y X
Z
t=0.005s
Y X
Z
t=0.006s
Y X
Z
t=0.007s
Y X
Z
t=0.008s
Y X
Z
t=0.009s
Y X
Z
t=0.010s
Y X
Z
t=0.011s
Y X
Z
t=0.012s
Y X
Z
t=0.013s
Fig. 16. Impact of a disk on a wedge. Deformed configurations through the process
- Frictional case with µ = 0.4
A simple weak form for contact problems with Coulomb friction 279
small frictional slips at the contact interface. Eventually, one may say that the disk is in
equilibrium between the walls.
• Verification of the inequalities TN ≥ 0 and ‖TT‖ ≤ µTN
The inequality TN ≥ 0 in (16) is fully satisfied, except at some increments and some
nodes belonging to those elements overlapping the contact and the non-contact zones. The
Coulomb inequality ‖TT ‖ ≤ µTN in (17) is met with high precision (wherever TN ≥ 0).
• Contact stresses
The contact stress distribution in space and time is rather complex, as showed in
Fig. 17 and Fig. 18 for some typical increments.
Y X
Z
Y X
Z
Y X
Z
Fig. 17. Impact of a disk on a wedge. Frictionless case. Contact stresses
With friction µ = 0.4, the contact stresses present three profiles:
(i) In the first stage of the movement when the disk sinks into the wedge, Fig.
18a, there is slip at every contact nodes. The contact stresses are upward, in the opposite
direction of the movement.
(ii) In the second stage when the disk slightly rebounds backwards, Fig. 18b, there
is still slip everywhere but this time the contact stresses are downward.
(iii) In the last stage when the disk is stuck in the wedge, Fig. 18c, there is stick at
the contacting nodes, the contact stress profile is complex with their sum being zero in y-
and z-directions and thus satisfying the global equilibrium of the disk.
Y X
Z
Y X
Z
Y X
Z
Fig. 18. Impact of a disk on a wedge. Frictional case with µ = 0.4. Contact stresses
• Energies
The evolution in time of the system energies (kinetic energy, elastic strain energy
and total energy) is given in Fig. 19 for the frictionless case.
280 Nguyen Huynh Tan Tai, Le Van Anh
When the contact begins, the kinetic energy gradually drops to zero as the strain
energy increases, since the disk slows down and is more and more deformed. In the next
stage when the disk rebounds backwards, the kinetic energy is recovered whereas the strain
energy decreases. After the contact is over, the disk becomes circular again and the strain
energy stored during the impact is released in the form of kinetic energy. During the whole
process, the total energy is constant. It can be noted that the strain energy is small yet
not zero, which means that there are small oscillations of the disk after the rebound.
t (s)
E
(J
)
0.002 0.004 0.006 0.008 0.01 0.012 0.014
0
50
100
150
200
Deformation energy
Total energy
Kinetic energy
Fig. 19. Impact of a disk on a
wedge. Energy evolution in the
frictionless case
t (s)
E
(J
)
0.002 0.004 0.006 0.008 0.01 0.012 0.014
0
50
100
150
200
Deformation energy
Total energy
Kinetic energy
Fig. 20. Impact of a disk on
a wedge. Energy evolution with
friction µ = 0.4
In the frictional case, the energy evolution is more intricate than in the frictionless
case, as can be seen in Fig. 20. The curves present the same trends as in [21], although the
hypotheses adopted are different (the problem was solved in [21] in plain strain using the
Blatz-Ko hyperelastic constitutive law). The total energy decreases steadily and markedly
due to friction. At the end of the computation, there is a strong total energy loss and the
remaining energy is stored in the elastic strain energy.
6. CONCLUSIONS
The weak form (19) has been designed as an extension of the standard virtual
work principle to deal with the contact problem with Coulomb friction. Since it is a
genuine weighted residual relationship involving arbitrary (regular) virtual displacements
and multipliers, it can be discretized by means of the finite element method in a simple
way.
The finite element discretization process holds for any isoparametric finite element
on the contact surface. As the weak form already incorporates the contact laws, no local
integration of the frictional equations is required in the numerical solution procedure. The
A simple weak form for contact problems with Coulomb friction 281
numerical examples presented show the ability of the proposed formulation to deal with
quasistatic and dynamic contact problems, and many other examples can be found in [19].
ACKNOWLEDGMENTS
The authors would like to thank Prof. Nguyen Quoc Son, of Laboratoire de Mecanique
des Solides, Ecole Polytechnique in France, for his instructive remarks which have enabled
them to refine Proposition 2.
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Received July 1, 2011
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