This paper presented an algorithm of element finite method established for dynamic analysis of tunnel and foundation in space model subjected to moving loads of
vehicle. Numerical investigation has been carried out for an example with different parameters and showed effects of parameters of structure and load to the dynamic response
of tunnel-foundation system. The established finite element model and the computer
program were tested on a real tunnel. The obtained experimental results are acceptably
agreed with the numerical ones.
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al energy [9, 11] as
Πe =
1
2
∫
Ae
{
σif
}T
e
[Dcs]
{
σif
}
e
dAe −
∫
Ae
wp dAe =
1
2
{q}Te [Kp]e {q}e − {q}Te {P}e , (13)
with
[Kp]e︸ ︷︷ ︸
12×12
=
∫
Ae
[B]T [Dcs] [B] dAe,
{P}e︸︷︷︸
12×1
=
∫
Ae
[N]T p dAe,
(14)
are stiffness matrix and node loading vector of the element, respectively, [N]︸︷︷︸
1×12
=
[
N1 0 0 N2 0 0 N3 0 0 N4 0 0
]
, p is pressure of intensity.
Kinetic energy Te of element is determined by [9, 11]
Te =
1
2
∫
Ve
ρ {u˙}Te {u˙}e dVe
1
2
{q˙}Te
∫
Ve
ρ [N]T [N] dVe
{q˙}e = 12 {q˙}Te [M]e {q˙}e , (15)
where ρ-mass density, {q˙}e-velocity vector, and
[Mp]e =
∫
Ve
ρ [N]T [N] dVe. (16)
2.1.2. Elements for arc of arch
Suppose that arc of arch is a shallow cylindrical shell that can be described by
4 nodes flat shell elements with 6 degrees of freedom ui, vi, wi, θxi, θyi, θzi per node and
vector of element node displacement
{
qsh
}
e
=
{
{qp}Te
{
q f
}T
e
{
qθ
}T
e
}T
, (17)
where {qp}e︸ ︷︷ ︸
12×1
=
{
w1 θx1 θy1 w2 θx2 θy2 . . . w4 θx4 θy4
}T-vector of node dis-
placement of bending plate element,
{
q f
}
e =
{
u1 v1 u2 v2 u3 v3 u4 v4
}T-vector
of node displacement of tension or compression plate element
{
qθ
}
e=
{
θz1 θz2 θz3 θz4
}T
-vector of node twist surrounded the axis z of elements.
110 Nguyen Thai Chung, Do Ngoc Tien
Following [9, 12] the matrix of flat shell element stiffness can be derived as
[
Ksh
]
e︸ ︷︷ ︸
24×24
=
[Kp]e︸ ︷︷ ︸
12×12
[0]︸︷︷︸
12×8
[0]︸︷︷︸
12×4
[0]︸︷︷︸
8×12
[
K f
]
e︸ ︷︷ ︸
8×8
[0]︸︷︷︸
8×4
[0]︸︷︷︸
4×12
[0]︸︷︷︸
4×8
[Krz]e︸ ︷︷ ︸
4×4
, (18)
where: [Kp]e-stiffness matrix of bending plate element,
[
K f
]
e-stiffness matrix of tension
or compression plate element [9] and[Krz]e-stiffness matrix of twist plate element. In fact,
the components krz(i, j) of matrix [Krz]e are equal to zero (in the calculation these com-
ponents are considered to be very small, namely krz(i, j) = 10−3 ×max(k(m,n)), where
k(m,n) are components of matrices [Kp]e and
[
K f
]
e [9, 12]).
Similarly, mass matrix of flat shell element [9, 12] is
[
Msh
]
e︸ ︷︷ ︸
24×24
=
[Mp]e︸ ︷︷ ︸
12×12
[0]︸︷︷︸
12×8
[0]︸︷︷︸
12×4
[0]︸︷︷︸
8×12
[
M f
]
e︸ ︷︷ ︸
8×8
[0]︸︷︷︸
8×4
[0]︸︷︷︸
4×12
[0]︸︷︷︸
4×8
[Mrz]e︸ ︷︷ ︸
4×4
. (19)
Load vector, stiffness matrix and mass matrix of element shell in the global coordi-
nate system are determined as follow [12]{
qsh
}g
e
=
[
Tsh
]T {
qsh
}
e
,
[
Ksh
]g
e
=
[
Tsh
]T [
Ksh
]
e
[
Tsh
]
,
[
Msh
]g
e
=
[
Tsh
]T [
Msh
]
e
[
Tsh
]
,
(20)
where
[
Tsh
]
︸ ︷︷ ︸
24×24
is transformation coordinate system matrix.
2.1.3. Elements for foundation layers
For foundation layers, using the hexagonal 8-node element with 3 degrees of free-
dom of each node one can obtain the following relationship
{ε}e = [B] {q}e (21)
for strain vector {ε}e at a point of element and node displacement {q}e [9, 12]. In the
above equation the notations are introduced
{ε}e =
{
εx εy εz γxy γyz γzx
}T , [B] = [∂] [N] = [[B1] [B2] [B3] ... [B8]] ,
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 111
[N] is mode shape function matrix of element. Therefore, the stiffness matrix of element
is [12]
[K]e =
∫
Ve
[B]T [D] [B] dVe, (22)
with [D] is element material matrix. The mass load vector is determined by [12]
{P}e =
∫
Ve
[N]T {g} dV =
∫
Ve
[N]T
{
gx gy gz
}T dV, (23)
2.2. Modeling of vehicle movement on pavement plate
Let’s consider a four wheel vehicle modeled by 4-degree-of-freedom system which
moves on the pavement plate with the trajectory x = x(t), y = y(t) and velocity~v = ~v (t)
(see Fig. 3). The mass of vehicle body m is derived as absolute solid body and pavement
plate is springs with stiffness k f 1, k f 2, kr1, kr2 and damping elements c f , cr, respectively
(Fig. 4b, c). The inertia moment of vehicle body with center-of-mass G is J. The distances
from G to the front axle and rear axle are l f and lr, respectively. The position of vehicle
body is determined by parameters: vertical displacement u of center-of-mass G, rotation
displacement in plane xz, vertical displacement z f of front wheels, vertical displacement
zr of rear wheels. The considered system is 4-degree-of-freedom system [13]. Assumes
that vibration amplitude is small, vehicle body is in initial horizontal direction.
7
fz
fc
fm
u
rc
rz
rm
PL
x
O
z
y
kr1
kr1 kf1
kf2
l lr f
kr2
Plate
Car body
Moving trajectory
Wp
z
y
x1e
2e
Fr
Ff
a, Real model b, FEM model
Fig 3. Plate subjected to 4 degree of freedom vehicle load model
At a time, vehicle body is subjected to gravity force P = mg, the exiting forces Fr, Ff, and
inertia force mu, J (Fig.4a).
G
J
rF
mu
mg fF
u
lr l f
a, vehicle body b, wheel system, front suspension c, wheel system, rear suspension
Fig. 4. Applied forces of vehicle
Equilibrium equation system of vehicle body is
r f
r r f f
mu + F + F + mg = 0,
J - F l + F l = 0,
(24)
where u is vertical acceleration, is angular acceleration in the plane xz of vehicle body. The
equilibrium equations for wheels and suspension are
r1 1r 2r r1
r 2r r 2r r1 1r 2r r2 2r
r 2r r2 2r 2r r
k z z F
m z c z u k z z k z u 0,
c u z k u z F ,
r r
r r
l l
l l
(25)
f1 1f 2f f1
f 2f f 2f f1 1f 2f f 2 2f
f 2f f 2 2f 2f f
k z z F ,
m z c z u k z z k z u 0,
c u z k u z F .
f f
f f
l l
l l
(26)
where 2r is static deformation of spring with stiffness kr2 and 2f is static deformation of spring
with stiffness kf2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the systems
(4- degree of freedom vehicle)
(a) Real model
7
Tải trọng tác dụng
Quỹ đạo chuyển động
fz
fc
fm
u
rc
rz
rm
PL
PW
x
O
z
y
kr1
kr1 kf1
kf2
l lr f
kr2
Tấm
z
y
x1e
2e
Fr
Ff
a) Real model b) FEM model
Fig 3. Plate subjected to 4 degree of freedom vehicle load model
At a time, vehicle body is subjected to gravity force P = mg, the exiting forces Fr, Ff, and
inertia force mu, J (Fig.4a).
G
J
rF
mu
mg fF
u
lr l f
a, vehicle body b, wheel system, front susp nsion c, wheel system, rear suspension
Fig. 4. Applied forces of vehicle
Equilibrium equation system of vehicle body is
r f
r r f f
mu + F + F + mg = 0,
J - F l + F l = 0,
(24)
where is vertical acceleration, is angular acceleration in the plane xz of vehicle body. The
equilibrium equations for wheels and suspension are
r1 1r 2r r1
r 2r r 2r r1 1r 2r r2 2r
r 2r r2 2r 2r r
k z z F
m z c z u k z z k z u 0,
c u z k u z F ,
r r
r r
l l
l l
(25)
f1 1f 2f f1
f 2f f 2f f1 1f 2f f 2 2f
f 2f f 2 2f 2f f
k z z F ,
m z c z u k z z k z u 0,
c u z k u z F .
f f
f f
l l
l l
(26)
where 2r is static deformation of spring with stiffness kr2 and 2f is static deformation of spring
with stiffness kf2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the systems
(4- degree of freedom vehicle)
(b) FEM model
Fig. 3. Plate subjected o 4-degree-of-freedom vehicle load model
At a time, the vehicle body is subjected to gravity force P = mg, exiting forces
Fr, Ff , and inertia forces mu¨, J ϕ¨ (Fig. 4a).
The equilibrium equation system of vehicle body is written as follows
mu¨ + Fr + Ff + mg = 0,
J ϕ¨− Frlr + Ff l f = 0. (24)
112 Nguyen Thai Chung, Do Ngoc Tien
7
Tải trọng tác dụng
Quỹ đạo chuyển động
fz
fc
fm
u
rc
rz
rm
PL
PW
x
O
z
y
kr1
kr1 kf1
kf2
l lr f
kr2
Tấm
z
y
x1e
2e
Fr
Ff
a) Real model b) FEM model
Fig 3. Plate subjected to 4 degree of freedom vehicle load model
At a time, vehicle body is subjected to gravity force P = mg, the exiting forces Fr, Ff, and
inertia force mu, J (Fig.4a).
G
J
rF
mu
mg fF
u
lr l f
a, vehicle body b, wheel system, front suspension c, wheel system, rear suspension
Fig. 4. Applied forces of vehicle
Equilibrium equation system of vehicle body is
r f
r r f f
mu + F + F + mg = 0,
J - F l + F l = 0,
(24)
where u is vertical acceleration, is angular acceleration in the plane xz of vehicle body. The
equilibrium equations for wheels and suspension are
r1 1r 2r r1
r 2r r 2r r1 1r 2r r2 2r
r 2r r2 2r 2r r
k z z F
m z c z u k z z k z u 0,
c u z k u z F ,
r r
r r
l l
l l
(25)
f1 1f 2f f1
f 2f f 2f f1 1f 2f f 2 2f
f 2f f 2 2f 2f f
k z z F ,
m z c z u k z z k z u 0,
c u z k u z F .
f f
f f
l l
l l
(26)
where 2r is static deformation of spring with stiffness kr2 and 2f is static deformation of spring
with stiffness kf2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the systems
(4- degree of freedom vehicle)
(a) Vehicle body
7
Tải trọng tác dụng
Quỹ đạo chuyển động
fz
fc
fm
u
rc
rz
rm
PL
PW
x
O
z
y
kr1
kr1 kf1
kf2
l lr f
kr2
Tấm
z
y
x1e
2e
Fr
Ff
a) Real mod l b) FEM model
Fig 3. Plate subjected to 4 degree of freedom vehicle load model
At a time, vehicle body is subjected to gravity force P = mg, the exiting forces Fr, Ff, and
inertia force mu, J (Fig.4a).
G
J
rF
mu
mg fF
u
lr l f
a, vehicle body , wheel system, front suspension c, wheel system, rear suspension
Fig. 4. Applied forces of vehicle
Equilibrium equation system of vehicle body is
r f
r r f f
mu + F + F + mg = 0,
J - F l + F l = 0,
(24)
where u is vertical acceleration, is angular acceleration in the plane xz of vehicle body. The
equilibrium equ tions for wheels and suspension are
r1 1r 2r r1
r 2r r 2 r1 1r 2r r2 2r
r 2r r2 2r 2r r
k z z F
m z c z u k z z k z u 0,
c u z k u z F ,
r r
r r
l l
l l
(25)
f1 1f 2f f1
f 2f f 2f f1 1f 2f f 2 2f
f 2f f 2 2f 2f f
k z z F ,
m z c z u k z z k z u 0,
c u z k u z F .
f f
f f
l l
l l
(26)
where 2r is static deformation of spring with stiffness kr2 and 2f is static deformation of spring
with stiffness kf2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the systems
(4- degree of freedom vehicle)
(b) Wheel system,
front suspension
7
Tải trọng tác dụng
Quỹ đạo chuyển động
fz
fc
f
u
rc
rz
rm
PL
PW
x
O
z
y
kr1
kr1 kf1
kf2
l lr f
kr2
Tấm
z
y
x1e
2e
Fr
Ff
a) Real model b) FEM model
Fig 3. P ate subjected to 4 degree of freedom vehicle load model
At a time, vehicle body is subjected to gravity force P = mg, the exiting forces Fr, Ff, and
inertia force mu, J (Fig.4a).
G
J
rF
mu
mg fF
u
lr l f
a, vehicle body b, wheel system, front suspension c, wheel syste , rear suspension
Fig. 4. Applied forces o vehicle
Equilibrium equation system of vehicle body is
r f
r r f f
mu + F + F + mg = 0,
J - F l + F l = 0,
(24)
where u is vertical acceleration, is angular acceleration in the plane xz of vehicle body. The
equilibrium equations for wheels and suspension are
r1 1r 2r r1
r 2r r 2r r1 1r 2r r2 2r
r 2r r2 2r 2r r
k z z F
m z c z u k z z k z u 0,
c u z k u z F ,
r r
r r
l l
l l
(25)
f1 1f 2f f1
f 2f f 2f f1 1f 2f f 2 2f
f 2f f 2 2f 2f f
k z z F ,
m z c z u k z z k z u 0,
c u z k u z F .
f f
f f
l l
l l
(26)
where 2r is static deformation of spring with stiffness kr2 and 2f is static deformation of spring
with stiffness kf2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the systems
(4- degree of freedom vehicle)
(c) Wheel sy tem,
rear suspension
Fig. 4. Applied forces of vehicle
where u¨ is vertical ac eler i n, ϕ¨ is angul r acceleration in th plane xz of vehicle body.
The equilibrium equations for wheels and suspension are
kr1 (z1r − z2r) = Fr1,
mr z¨2r + cr (z˙2r − u˙ + ϕ˙lr)− kr1 (z1r − z2r) + kr2 (z2r − u + ϕlr) = 0,
cr (u˙− z˙2r − ϕ˙lr) + kr2 (u− z2r − ϕlr − δ2r) = Fr.
(25)
k f 1
(
z1 f − z2 f
)
= Ff 1,
m f z¨2 f + c f
(
z˙2 f − u˙ + ϕ˙l f
)− k f 1 (z1 f − z2 f )+ k f 2 (z2 f − u + ϕl f ) = 0,
c f
(
u˙− z˙2 f + ϕ˙l f
)
+ k f 2
(
u− z2 f + ϕl f − δ2 f
)
= Ff .
(26)
where δ2r is static deformation of spring with stiffness kr2 and δ2 f is static deformation of
spring with stiffness k f 2.
Combining (24), (25) and (26) leads to the differential equations for vibration of the
systems (4-degree-of-free om vehicle)
mu¨+cr(u˙− z˙2r − ϕ˙lr)+c f
(
u˙− z˙2 f + ϕ˙l f
)
+kr2(u− z2r − ϕlr)+k f 2
(
u− z2 f + ϕl f
)
=0,
J ϕ¨−lrcr(u˙−z˙2r− ϕ˙lr)+l f c f
(
u˙−z˙2 f+ ϕ˙l f
)−lrkr2(u−z2r−ϕlr)+l f k f 2(u−z2 f+ϕl f )=0,
mr z¨2r − cr (u˙− z˙2r − ϕ˙lr) + kr1 (z2r − z1r)− kr2 (u− z2r − ϕlr) = 0,
m f z¨2 f − c f
(
u˙− z˙2 f + ϕ˙l f
)
+ k f 1
(
z2 f − z1 f
)− k f 2 (u− z2 f + ϕl f ) = 0,
(27)
where z1r, z1 f are vertical displacements of pavement plate at position of contact with the
wheels and z2r, z2 f are displacements of mass mr and m f , respectively.
Let (ξ1, η1) and (ξ2, η2) be coordinates of the contact points where loads Fr1 and Fr2
are applied to elements e1 and e2 of pavement plate. The global coordinate systems of the
plate elements are (x1 = x01 + ξ1, y1 = y01 + η1) and (x2 = x02 + ξ2, y2 = y02 + η2). Using
the representation (9) for flexural displacement we obtain
z1r = [Ne1 (ξ1, η1)] {qe1} = [N (ξ1, η1)] [G]−1 {qe1} ,
z1 f = [Ne2 (ξ2, η2)] {qe2} = [N (ξ2, η2)] [G]−1 {qe2} ,
(28)
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 113
where [G]︸︷︷︸
12×12
is matrix of geometrical properties for the elements [9]. Substituting (28) into
(27), leads to the equation
[Mv] {q¨v}+ [Cv] {q˙v}+ [Kv] {qv} = {Fv} , (29)
where vectors of acceleration, velocity and displacement {q¨v} , {q˙v} , {qv}; matrices of
mass, damping and stiffness [Mv], [Cv], [Kv] and load vector {Fv} are determined, re-
spectively, as
{qv} = {u ϕ z2r z2 f}T , [Mv] =
m 0 0 0
0 J 0 0
0 0 mr 0
0 0 0 m f
, (30)
[Cv] =
cr + c f l f c f − lrcr −cr −c f
l f c f − lrcr l2r cr + l2f c f lrcr −l f c f
−cr lrcr cr 0
−c f −l f c f 0 c f
, {Fv} =
0
0
k1r [N (ξ1, η1)] [G]
−1 {qe1}
k1 f [N (ξ2, η2)] [G]
−1 {qe2}
,
(31)
[Kv] =
kr2 + k f 2 l f k f 2 − lrkr2 −kr2 −k f 2
l f k f 2 − lrkr2 l2r kr2 + l2f k f 2 lrkr2 −l f k f 2
−kr2 lrkr2 kr1 + kr2 0
−k f 2 −l f k f 2 0 k f 1 + k f 2
. (32)
Assuming that the plate element e1 is subjected to moving load Fr1 and element e2
subjected to moving load Ff 1, the forces can be rewritten as
Fr1 = kr1 (z1r − z2r) = mr z¨2r − cr (u˙− z˙2r − ϕ˙lr)− kr2 (u− z2r − ϕlr) ,
Ff 1 = k f 1
(
z1 f − z2 f
)
= m f z¨2 f − c f
(
u˙− z˙2 f + ϕ˙l f
)− k f 2 (u− z2 f + ϕl f ) . (33)
By using Delta-Dirac function δ(·) [9, 11, 14] the concentrated loads (33) can be
represented as the distribution force pi(ξ,η,t) as follows
pr1 (ξ, η, t) = Fr1 · δ (ξ − ξ1) · δ (η − η1) ,
p f 1 (ξ, η, t) = Ff 1 · δ (ξ − ξ2) · δ (η − η2) . (34)
Therefore, the node load vector of element becomes [9]
{Fe1} = [N (ξ1, η1)]T Fr1, {Fe2} = [N (ξ2, η2)]T Ff 1. (35)
Substituting (33) into (35), leads to{
Fe1
}
=
[
M1r
] {q¨v}+ [C1r] {q˙v}+ [K1r] {qv} ,{
Fe2
}
=
[
M1 f
] {q¨v}+ [C1 f ] {q˙v}+ [K1 f ] {qv} , (36)
114 Nguyen Thai Chung, Do Ngoc Tien
where[
M1r
]
=
[
0 0 [N (ξ1, η1)]
T mr 0
]
,
[
M1 f
]
=
[
0 0 0 [N (ξ2, η2)]
T m f
]
,[
C1r
]
=
[
− [N (ξ1, η1)]T cr [N (ξ1, η1)]T crlr [N (ξ1, η1)]T cr 0
]
,[
C1 f
]
=
[
− [N (ξ2, η2)]T c f − [N (ξ2, η2)]T c f l f 0 [N (ξ2, η2)]T c f
]
,[
K1r
]
=
[
− [N (ξ1, η1)]T kr2 [N (ξ1, η1)]T kr2lr [N (ξ1, η1)]T kr2 0
]
,[
K1 f
]
=
[
− [N (ξ2, η2)]T k f 2 − [N (ξ2, η2)]T k f 2l f 0 [N (ξ2, η2)]T k f 2
]
.
So, the equations of motion for elements e1 and e2 get to be
[Me1 ] {q¨e1}+ [Ce1 ] {q˙e1}+ [Ke1 ] {qe1} = {Fe1} , (37)
[Me2 ] {q¨e2}+ [Ce2 ] {q˙e2}+ [Ke2 ] {qe2} = {Fe2} , (38)
with [Mei ] , [Cei ] , [Kei ], (i = 1, 2) are matrices of mass, damping and stiffness, respectively.
Introducing the node displacement vector
{qe}v =
{
{qe1}T {qe2}T {qv}T
}T
, (39)
composed off those of the plate elements e1, e2 and body car and combining Eqs. (36) (37),
(38) with (29) allow the equations of motion for vehicle system and pavement elements
to be written in the matrix form
[Me]v {q¨e}v + [Ce]v {q˙e}v + [Ke]v {qe}v = {Fe}v , (40)
with
[Me]v =
[Me1] [0] − [M1r][0] [Me2] − [M1 f ]
[0] [0] [Mv]
= [Met ] + [Mep]v ,
[Ke]v =
[Ke1] [0] − [K1r][0] [Ke2] − [K1 f ]
[0] [0] [Kv]
= [Ket ] + [Kep]v ,
[Ce]v =
[Ce1] [0] − [C1r][0] [Ce2] − [C1 f ]
[0] [0] [Cv]
= [Cet ] + [Cep]v , {Fe}v =
{0}{0}{Fv}
.
Assembling all elements matrices and nodal force vectors the governing equations
of motions of the total system can be derived as
[M] {q¨}+ [C] {q˙}+ [K] {q} = {F} , (41)
with
[M] =∑
e
[Met ] +∑
e
[
Mep
]
v
, [K] =∑
e
[Ket ] +∑
e
[
Kep
]
v
,
[C] =∑
e
[Cet ] +∑
e
[
Cep
]
v
, {F} =∑
e
{Fe}v,
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 115
This is a linear differential equation system with time dependence coefficient that
can be solved by using direct integration Newmark’s method. A Matlab program named
by 3D Structures Moving 2014 was conducted to solve equation (41).
3. NUMERICAL ANALYSIS
3.1. Validation of computer program
To validate the present approach, consider a tunnel with square box cross section
area Htun ×Wtun = 4 m×4 m, thickness of wall ttun = 0, 5 m, length Ltun = 10 m in
the homogeneous foundation, depth from center of tunnel section to freely surface of
foundation is htun = 4 m, subjected by concentric loading at the center point of pave-
ment, load law P(t) = P0 sin 2pi f t, with P0 = 50000 N, f = 10 Hz. Tunnel is made
by concrete with elastic modulus Etun = 0.34 × 107 N/cm2, Poisson ratio νtun = 0.3,
mass density ρtun = 2.5 × 10−3 kg/cm3; characteristic of foundation: elastic modulus
E f = 0.2 × 106 N/cm2, Poisson ratio ν f = 0.35, mass density ρ f = 1.8 × 10−3 kg/cm3.
The considered region dimensions: Hs ×Ws × Ls = 20 m×40 m×10 m. The results are
obtained by using 3D Structures Moving 2014 and Ansys 13.0 programs. The first three
of fundamental frequency and displacement amplitude at loaded point for two methods
are shown in Tab. 1.
Table 1. Comparison between present results with Ansys software results
Fundamental frequency Maximum displacement
Characteristics f1[Hz] f2[Hz] f3[Hz] Wmax[cm]
Method
Ansys 13.0 36.21 98.36 142.84 0.268
Present 36.54 98.69 143.18 0.271
Different (%) 0.91 0.34 0.25 1.12
This comparison shows that the good agreements are obtained, the difference is
very small (≤ 0.25% for fundamental frequency and 1.12% - for displacement).
3.2. Numerical results
A concrete double tunnel with symmetric cross section, as shown in Fig. 5 is con-
sidered. The tunnel is subjected to moving load of 4-wheel vehicle which moves in lon-
gitudinal direction of the left tunnel with velocity v = 60 km/h. Length of tunnel L =
20 m; wall thickness t1 = t2 = W2 −W1 = 5.95 m – 4.45 m = 1.5 m; wall height H3 = 3.6 m;
pavement thickness H1 = 0.4 m; tunnel width 2W1 = 9.5 m, radius of arch R1 = 6.5 m, R2
= 8.5 m, respectively. Dimension of cross section of hollow box (serape 2 single tunnels)
ELH × ELW = 3 m×1.5 m. Elastic modulus of concrete Ec = 3.4×1010 N/m2; Poisson ratio
νc = 0.3; mass density ρc = 2500 kg/m3. Accuracy of iteration εd = 0.5%, considered re-
gion dimensions H ×W × L = 20 m × 70 m × 20 m. Three foundation layers 1, 2, 3 with
properties are presented in Tab. 2.
Vehicle body mass m = 7000 kg, m f = 600 kg, mr = 900 kg, inertia moment of ve-
hicle body about the center-of-mass J = 30000 kgm2, distances from front wheel and
116 Nguyen Thai Chung, Do Ngoc Tien
Table 2. Foundation properties
Layer Depth (m) E f (N/cm2) ν f ρ f (kg/m3)
1 1.4 0.20×106 0.28 1.70×103
2 4.2 0.44×106 0.25 1.90×103
3 18.6 0.90×106 0.25 2.15×103
rear wheel are l f = 3.2 m, lr = 1.8 m, respectively, elastic spring stiffness are k f 1 =
3000000 N/m, k f 2 = 450000 N/m, kr1 = 4000000 N/m, kr2 = 700000 N/m, damping co-
efficients c f = cr = 500 Ns/m. Considered points are A(−6.7, 10, 10.8) , the middle of
pavement and in the foundation surface. The system model and FEM configuration are
shown in Figs. 5-6.
11
Remark: Clearly, this comparison once again shows that the good agreements are obtained,
the difference is very small (≤ 0,25% for fundamental frequency and 1,12% - for forced
vibration).
3.2. Numerical results
A concrete double tunnel with symmetric cross section, as shown in Fig 5 is considered. The
tunnel is subjected to moving load of 4-wheel vehicle which moves in longitudinal direction of
the left tunnel with velocity v = 60km/h. Length of tunnel L = 20m; wall thickness t1 = t2 = W2 –
W1 = 5,95m – 4,45m = 1,5m; wall height H3 = 3,6m; pavement thickness H1 = 0,4m; tunnel
width 2W1 = 9.5m, radius of arch R1 = 6.5m, R2 = 8.5m, respectively. Dimension of cross
section of hollow box (serape 2 single tunnels) ELH×ELW = 3m×1.5m. Elastic modulus of
concrete Ec = 3.4×10
10
N/m2; Poisson ratio c = 0.3; mass density c = 2500kg/m
3
. Accuracy of
iteration d = 0.5%, considered region dimensions H×W×L = 20m×70m×20m. Three foundation
layers 1, 2, 3 with properties are presented in Table 2.
Table 2. Foundation properties
Layer Depth (m) Ef(N/cm
2
) f f(kg/m
3
)
1 1,4 0,20106 0, 8 1,70103
2 4,2 0,44106 0, 1,90103
3 18,6 0,90106 0,25 2,15103
V hicle body mass m = 7000kg, mf = 600kg, mr = 900kg, inertia moment of vehicle body
about the center-of-mass J = 30000kgm
2
, distances from front wheel and rear wheel are lf =
3.2m, lr = 1.8m, respectively, elastic spring stiffness are kf1 = 3000000N/m, kf2 = 450000N/m,
kr1 = 4000000N/m, kr2 = 700000N/m, damping coefficients cf = cr = 500Ns/m. Considered
points are A(-6.7,10,10.8) , the middle of pavement and in the foundation surface. The system
model and FEM configuration are shown in Figs.5-6.
H
2
H
3
W2 W1
H1
R1R2
ELW
ELHH
4H
5
W3
1
2
3
L B
LB
y
x
z
L/2
L/2
Fig. 5. Problem model
Fig. 5. Model of double tunnel
12
z
y
x
Fig. 6. Configuration of FEM.
Displacement and acceleration response results of considered points are shown in Fig.7
and Fig.8.
Fig.7. Vertical displacement response at A Fig.8. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displacement responses at the point A are shown in Fig.9 with the speed of vehicle various
from 50km/h to 100km/h, variation of maximum displacement at point B are presented in Fig.10.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2
-0.045
-0.04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
e
rt
ic
a
l d
is
p
la
c
e
m
e
n
t
[c
m
]
60km/h
60km/h
70km/h
80km/h
90km/h
100km/h
Fig. 9.Vertical displacement response at point A Fig.10. Variation of maximum displacement at point B
Fig. 6. Configuration of FEM
Fig. 7 shown the relationship of displacement amplitude at point A (z-dir.) and
frequency. And we have 4 first natural frequency are f1 = 19.82, f2 = 20.89, f3 =
21.93, f4 = 22.16 (Hz). Displacement and acceleration response results of considered
points are shown in Figs. 8-9.
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 117
12
Fig.7 shown the relationship of displacement amplitude at point A (z-dir.) and frequency.
10 12 14 16 18 20 22 24 26 28 30
0
0.2
0.4
0.6
0.8
1
1.2
1.4
x 10
-4
Frequency f[Hz]
D
is
p
.
a
m
p
li
tu
d
e
z
-d
ir
.[
m
]
Fig.7. Vertical displacement amplitude – frequency
And we have 4 first natural frequency are f1=19.82, f2=20.89, f3=21.93, f4=22.16 (Hz).
Displacement and acceleration response results of considered points are shown in Fig.8
and Fig.9.
Fig.8. Vertical displacement response at A Fig.9. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displacement responses at the point A are shown in Fig.10 with the speed of vehicle various
from 50km/h to 100km/h, variation of maximum displacement at point B are presented in Fig.11.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2
-0.045
-0.04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
e
rt
ic
a
l d
is
p
la
c
e
m
e
n
t
[c
m
]
60km/h
60km/h
70km/h
80km/h
90km/h
100km/h
Fig.10.Vertical displacement response at point A Fig.11. Variation of maximum displacement at point B
Fig. 7. Vertical displacement amplitudefrequency
12
z
y
x
Fig. 6. Configuration of FEM.
Displacement and acceleration response results of considered points are shown in Fig.7
and Fig.8.
Fig.7. Vertical displacement response at A Fig.8. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displacement responses at the point A are shown in Fig.9 with the speed of vehicle various
from 50km/h to 100km/h, variation of maximum displacement at point B are presented in Fig.10.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2
-0.045
-0.04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
er
tic
al
d
is
pl
ac
em
en
t [
cm
]
60km/h
60km/h
70km/h
80km/h
90km/h
100km/h
Fig. 9.Vertical displacement response at point A Fig.10. Variation of maximum displacement at point B
Fig. 8. Vertical displacement response at A
12
z
y
x
Fig. 6. Configurati n of FEM.
Displac ment and acceleration respons results of considered points are shown in Fig.7
and Fig.8.
Fig.7. Vertical displac ment response at A Fig.8. Vertic l acceleration response at A
3.2.1. Effect of speed f load
Displac ment responses at the point A are show in Fig.9 wi the speed of vehicle various
from 50km/h to 100km/h, variati n of maxi um displac ment at point B are presented in Fig.10.
0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 2
-0.045
- .04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
er
tic
al
d
is
pl
ac
em
en
t [
cm
]
60km/h
60km/h
70km/h
80km/h
90km/h
100km/h
Fig. 9.Vertical displac ment response at point A Fig 10. Variati n of maxi um displac ment at point B
Fig. 9. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displacement responses at the point A are shown in Fig. 10 with the speed of ve-
hicle various from 50 km/h to 100 km/h, variation of maximum displacement at point B
are presented in Fig. 11.
12
z
y
x
Fig. 6. Configuration of FEM.
Displacement and acceleration response results of considered points are shown in Fig.7
and Fig.8.
Fig.7. Vertical displacement response at A Fig.8. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displacement responses at the point A are shown in Fig.9 with the speed of vehicle various
from 50km/h to 100km/h, variation of maximum displacement at point B are presented in Fig.10.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2
-0.045
-0.04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
er
tic
al
d
is
pl
ac
em
en
t [
cm
]
60km/h
60km/h
70km/h
80km/h
90km/h
100km/h
Fig. 9.Vertical displacement response at point A Fig.10. Variation of maximum displacement at point B
Fig. 10. Vertical displacement response at
point A 12
z
y
x
Fig. 6. Configuration of FEM.
Displacement and acceleration response results of considered points are shown in Fig.7
and Fig.8.
Fig.7 Vertical displacement response at A Fig.8. Vertical acceleration response at A
3.2.1. Effect of speed of load
Displ cement responses at the point A are shown in Fig.9 with the speed of vehicle various
from 50km/h to 100km/h, variation of maximum displacement at point B are presented in Fig.10.
0 .2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2
-0.045
-0.04
-0.035
-0.03
-0.025
-0.02
-0.015
-0.01
-0.005
0
0.005
Time t[s]
V
er
tic
al
d
is
pl
ac
em
en
t [
cm
]
60k /h
60k /h
70k /h
80k /h
90k /h
100k /
Fig. 9.Vertical displacement response at point ig.10. ariation of axi u displacement at point B
Fig. 11. Variation of maximum displacement
at point B
118 Nguyen Thai Chung, Do Ngoc Tien
3.2.2. Effect of foundation surrounding tunnel
In this section, elastic modulus E3 of third foundation layer (the foundation sur-
rounds tunnel) varies from 0.2×106 N/cm2 to 2.0×106 N/cm2. Obtained dynamic re-
sponses are shown in Figs. 12-13.
13
3.2.2. Effect of foundation surrounding tunnel
In this section, elastic modulus E3 of third foundation layer (the foundation surrounds tunnel)
varies from 0,2106N/cm2 to2,0106N/cm2. Obtained dynamic responses are shown in Figs.12-13.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-7
-6
-5
-4
-3
-2
-1
0
1
2
x 10
-4
Time [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
0.2e6
0.5e6
0.7e6
0.9e6
1.2e6
1.4e6
1.7e6
2.0e6
Fig.12.Vertical displacement response at point A Fig.13.Maximum displacement at point B
3.2.3. Effect of tunnel type
Consider two tunnel types: box – arch section (Type 1) and box section (Type 2) with the same
pavement, depth of wall and total section area. Dynamic responses of point A are as Figs. 14-15.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
x 10
-4
Time [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
Type 1
Type 2
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
1
x 10
6
Time [s]
S
tr
es
s
[N
/m
2 ]
Xicma
x
-Type 1
Xicma
x
-Type 2
Xicma
y
-Type 1
Xicma
y
-Type 2
Fig.14.Vertical displacement responses Fig.15. Stress responses
Remark: The result shows that displacement, acceleration and stress of arc of arch tunnel
are smaller than those of flat roof tunnel, and therefore load-carrying capacity of arc of arch
tunnel is larger than one of flat roof tunnel.
4. EXPERIMENTAL VALIDATION
4.1. Experimental model and equipment
4.1.1. Tunnel
Double tunnel, N
o
05-TEDI-003-HĐ at Km7+358 Lang - Hoa Lac expressway, Hanoi, cross
section is rectangular box, made by reinforced concrete.
Fig. 12. Vertical displacement response at
point A
13
3.2.2. Effect of fo ti s rr i t l
In thi section, elasti l 3 f t ir f ti l r (the foundation surrounds tun el)
varies fro 0,2106 /c 2 t , 6 / 2. t i i res onses are shown in Figs.12-13.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-7
-6
-5
-4
-3
-2
-1
0
1
2
x 10
-4
Ti e [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
.
.
.
.
1.7e6
2.0e6
Fig.12.Vertical dis la t r s s t i t i . . i u displacement at point B
3.2.3. Effect of tu el type
Consider t o tunnel types: box – arch section ( ype 1) and box section (Type 2) with the same
pavement, depth of all and total section area. yna ic responses of point are as Figs. 14-15.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
x 10
-4
Time [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
Type 1
Type 2
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
1
x 10
6
Time [s]
S
tr
es
s
[N
/m
2 ]
Xicma
x
-Type 1
Xicma
x
-Type 2
Xicma
y
-Type 1
Xicma
y
-Type 2
Fig.14.Vertical displacement responses Fig.15. Stress responses
Remark: The result shows that displacement, acceleration and stress of arc of arch tunnel
are smaller than those of flat roof tunnel, and therefore load-carrying capacity of arc of arch
tunnel is larger than one of flat roof tunnel.
4. EXPERIMENTAL VALIDATION
4.1. Experimental model and equipment
4.1.1. Tunnel
Double tunnel, N
o
05-TEDI-003-HĐ at Km7+358 Lang - Hoa Lac expressway, Hanoi, cross
section is rectangular box, made by reinforced concrete.
Fig. 13. Maximum displacement at point B
3.2 3. Effect of tunnel type
Consider two tunnel types: box-arch section (Type 1) and box section (Type 2) with
the same pavement, depth of wall and total section area. Dynamic responses of point A
are shown in Figs. 14-15. The result shows that the displacement, acceleration and stress
of arc of arch tunnel are smaller than those of flat roof tunnel, and therefore load-carrying
capacity of arc of arch tunnel is larger than one of flat roof tunnel.
13
3.2.2. Effect of foundation surrounding tunnel
In this section, elastic modulus E3 of third foundation layer (the foundation surrounds tunnel)
varies from 0,2106N/cm2 to2,0106N/cm2. Obtained dynamic responses are shown in Figs.12-13.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-7
-6
-5
-4
-3
-
-1
0
1
2
x 10
-4
Time [s]
V
e
rt
ic
a
l
d
is
p
la
c
e
m
e
n
t
[m
]
0.2e6
0.5e6
0.7e6
0.9e6
1.2e6
1.4e6
1.7e6
2.0e6
Fig.12.Vertical displacement response at point A Fig.13.Maximum displacement at point B
3.2.3. Ef ect of tunnel type
Consider two tunnel types: box – arch section (Type 1) and box section (Type 2) with the same
pavement, depth of wall and total section area. Dynamic responses of point A are as Figs. 14-15.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
x 10
-4
Time [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
Type 1
Type 2
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
1
x 10
6
Time [s]
S
tr
e
s
s
[
N
/m
2
]
Xicma
x
-Type 1
Xicma
x
-Type 2
Xicma
y
-Type 1
Xicma
y
-Type 2
Fig.14.Vertical displacement responses Fig.15. Stress responses
Remark: The result shows that displacement, acceleration and stress of arc of arch tunnel
are smaller than those of flat roof tunnel, and therefore load-carrying capacity of arc of arch
tunnel is larger than one of flat roof tunnel.
4. EXPERIMENTAL VALIDATION
4.1. Experimental model and equipment
4.1.1. Tunnel
Double tunnel, N
o
05-TEDI-003-HĐ at Km7+358 Lang - Hoa Lac expressway, Hanoi, cross
section is rectangular box, made by reinforced concrete.
Fig. 14. Vertical displacement responses
13
3.2.2. Effect of foundation surrounding tunnel
In this section, elastic modulus E3 of third foundation layer (the foundation surrounds tunnel)
varies from 0,2106N/cm2 to2,0106N/cm2. Obtained dynamic responses are shown in Figs.12-13.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-7
-6
-5
-4
-3
-2
-1
0
1
2
x 10
-4
Time [s]
V
e
rt
ic
a
l
d
is
p
la
c
e
m
e
n
t
[m
]
0.2e6
0.5e6
0.7e6
0.9e6
1.2e6
1.4e6
1.7e6
2.0e6
i . . ert cal i lace e t res se at point Fig.13. axi u displaceme t at point B
. . . f t f t l t
i r t t l t s: arch section ( ype 1) and box section (Type 2) with the same
t, t f ll t t l secti n area. yna ic responses of point A are as Figs. 14- 5.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-
- .
-
- .
-
- .
.
x 10
-4
Ti e [s]
V
er
ti
ca
l d
is
p
la
ce
m
en
t
[m
]
Type 1
Type 2
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-3
-2.5
-2
-1.5
-1
-0.5
0
0.5
1
x 10
6
Time [s]
S
tr
es
s
[N
/m
2
]
Xicma
x
-Type 1
Xicma
x
-Type 2
Xicma
y
-Type 1
Xicma
y
-Type 2
i . . rti l is l e t responses Fig.15. Stres responses
: r s lt s s t at isplace ent, acceleration and stress of arc of arch tun el
are s aller t a t se f flat r f t nel, and therefore load-carrying capacity of arc of arch
tunnel is larger than one of flat roof tunnel.
. I I I
4.1. xperi ental odel and equip ent
4.1.1. Tunnel
Double tunnel, N
o
05-TEDI-003-HĐ at K 7+358 Lang - Hoa Lac expressway, Hanoi, cross
section is rectangular box, made by reinforced concrete.
Fig. 15. Stress responses
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 119
4. EXPERIMENTAL VALIDATION
4.1. Experimental model and equipment
4.1.1. Tunnel
The experiment was carried out for the double tunnel, N◦ 05-TEDI-003-H at Km7
+358 Lang-Hoa Lac expressway, Hanoi. Its cross section is rectangular box, made by
reinforced concrete, (see Fig. 16).
14
a) Experimental tunnel b) Cross section dimension
Fig. 15.Configuration of experimental tunnel
4.1.2. Loading generation
Loading equipment is passenger cars four wheels, conversion parameters: m = 6600kg, mf =
320kg, mr = 410kg, J = 21000kgm
2
, lf = 3,2m, lr = 1,8m, kf1 = 2400000N/m, kr1 = 3600000N/m,
kf2 = 390000N/m, kr2 = 540000N/m, cf = cr = 460Ns/m.
4.1.3. Acceleration sensor, resistors plate:
Acceleration sensors ARF-10A are placed on the right of pavement plate to determine
vertical acceleration and at the longitudinal tunnel position; resistor plate is attached 1m from
acceleration sensor position in longitudinal tunnel to determined relative deformation.
Accelerometer specifications are: mass: 2g, sensitivity: 0,5mV/(m/s
2
), the frequency ranges: 1 to
12000 (10%)Hz, peak acceleration: 10m/s2, accuracy: ≤ 0.05%.
In the experimental procedure, resistors plate is attached on the pavement and is deformed
according to the deformation of pavement.
4.1.3. Dynamic measurement system:
a) Experimental equipment preparation b) Acceleration and deformation sensor disposition
Fig.16. Experimental preparation
(a) rimental tunnel
14
a) Experimental tunnel b os section dimension
Fig. 15.Configuration of experimental tunnel
4.1.2. Loading generation
Loading equipment is passenger cars four wheels, conversion parameters: m = 6600kg, mf =
320kg, mr = 410kg, J = 21000kgm
2
, lf = 3,2m, lr = 1,8m, kf1 = 2400000N/m, kr1 = 360000 N/m,
kf2 = 390000N/m, kr2 = 540000N/m, cf = cr = 460Ns/m.
4.1.3. Acceleration sensor, resistors plate:
Acceleration sensors ARF-10A are placed on the right of pavement plate to determine
v rtic l accelerati n and at he longitudinal tunnel position; resistor plate is attached 1m from
acceleration sensor position in longitudinal tunnel to determined relative deformation.
Accelerometer specifications are: mass: 2g, sensitivity: 0,5mV/(m/s
2
), the frequency ranges: 1 to
12000 (10%)Hz, peak acceleration: 10m/s2, accuracy: ≤ 0.05%.
In the experimental procedure, resistors plate is attached on the pavement nd is deformed
according to the deformation of pavement.
4.1.3. Dynamic measurement system:
a) Experimental equipment preparation b) Acceleration and deformation sensor disposition
Fig.16. Experimental preparation
(b) Cross ection dimensio
Fig. 16. Configuration of experimental tunnel
4.1.2. Loading generation
Loading is excited by passenger cars of four wheels and conversion parameters:
m = 6600 kg, m f = 320 kg, mr = 410 kg, J = 21000 kgm2, l f = 3.2 m, lr = 1, 8 m, k f 1
= 2400000 N/m, kr1 = 3600000 N/m, k f 2 = 390000 N/m, kr2 = 540000 N/m, c f = cr =
460 Ns/m.
4.1.3. Acceleration sensor, resistors plate
Acceleration sensors ARF-10A are placed on the right of pavement plate to deter-
mine vertical acceleration and at the longitudinal tunnel position; resistor plates are at-
tached 1m from acc leration sens r position in longitudinal tunnel to determined relative
deformation. Accelerometer specifications are: mass: 2 g, sensitivity: 0.5 V/(m/s2), the
frequency ranges: 1 to 12000 (±10%) Hz, peak acceleration: 10 m/s2, accuracy: ≤ 0.05%
(see Figs. 17-18).
4.1.4. Dynamic measurement system
Dynamic measurement system SDA-810C (Japan), made in 2010, with: 8 chan-
nels, linear frequency response: 10 kHz, electronic source: DC10.5-30V 1.4A; AC170-250V
50/60 Hz 25VA, accuracy: 0.0025%, resolution ADC: 16 bit, sampling rate: 19.2 kHz. This
equipment gathers in-situ data that are stored into a computer.
Consider thre ve ocity l vels of vehicle 30 km/h, 40 km/h, 50 km/h, urcharge 15
times for each velocity level (n = 15).
120 Nguyen Thai Chung, Do Ngoc Tien
14
a) Experimental tunnel b) Cross section dimension
Fig. 15.Configuration of experimental tunnel
4.1.2. Loading generation
Loading equipment is passenger cars four wheels, conversion parameters: m = 6600kg, mf =
320kg, mr = 410kg, J = 21000kgm
2
, lf = 3,2m, lr = 1,8m, kf1 = 2400000N/m, kr1 = 3600000N/m,
kf2 = 390000N/m, kr2 = 540000N/m, cf = cr = 460Ns/m.
4.1.3. Acceleration sensor, resistors plate:
Acceleration sensors ARF-10A are placed on the right of pavement plate to determine
vertical acceleration and at the longitudinal tunnel position; resistor plate is attached 1m from
acceleration sensor position in longitudinal tunnel to determined relative deformation.
Accelerometer specifications are: mass: 2g, sensitivity: 0,5mV/(m/s
2
), the frequency ranges: 1 to
12000 (10%)Hz, peak acceleration: 10m/s2, accuracy: ≤ 0.05%.
In the experimental procedure, resistors plate is attached on the pavement and is deformed
according to the deformation of pavement.
4.1.3. Dynamic measurement system:
a) Experimental equipment preparation b) Acceleration and deformation sensor disposition
Fig.16. Experimental preparation
(a) Experimental equipment preparation
a) Experimental tunnel b) Cross section dime sion
Fig. 15.Configurati n of experimental tunnel
. . . oading generation
ading equipment is passenger cars four wheels, conversion parameters: m = 6600kg, mf =
, r = 410kg, J = 21 0kgm
2
, lf = 3,2m, lr = 1,8m, kf1 = 24 000N/m, kr1 = 3600000N/m,
f 0000N/m, kr2 = 54 0N/m, cf = cr = 460Ns/m.
. . cceleration sensor, re istors plate:
celeration sensors ARF-10A are placed on the right of pavement plate to determine
ti al acceleration and a the longitudinal tunnel position; resistor plate is attached 1m from
l ration sensor pos tion in longitudinal tunnel to determined relativ deformation.
lero eter specifications are: mass: 2g, sensitivity: 0,5mV (m/s
2
), the frequency ranges: 1 to
(10 )Hz, peak a c leration: 10m/s2, accuracy: ≤ 0.05%.
the experimental procedure, resistors plate is ttached on the paveme t an is deformed
r ing to the deformation of pavement.
. . ynamic measurement system:
xperimental equipment prep ration b) Acceleratio and deformatio sensor disposition
Fig.16. Experimental reparation
(b) Acceleration and deformation sensor disposition
Fig. 17. Experimental preparation
15
a) Vehicle b) Result on the screen (01 time)
Fig.17. Experimental procedure
Dynamic measurement system SDA-810C (Japan), made in 2010, with: 8 channels, linear
frequency response: 10kHz, electronic source: DC10.5-30V 1.4A; AC170-250V 50/60Hz
25VA, accuracy: 0,0025%, resolution ADC: 16 bit, sampling rate: 19,2kHz. This equipment
gathers in-situ data that are stored into a computer.
Consider three velocity level of vehicle 30km/h, 40km/h, 50km/h, surcharge 15 times for
each velocity level (n = 15).
4.2. Experimental results
The comparison of results between theoretical calculation by 3D_Structures_Moving_2014
program and experimental method (with three velocity levels) is presented in Fig. 18 and table 3.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
Time t[s]
A
c
c
e
le
ra
ti
o
n
a
z
[m
/s
2
]
Experimental
Theoretical
Fig. 18. Vertical acceleration responses of considered point (V = 50km/h)
Table 3. Maximum acceleration of considered point
Car velocity V[km/h] 30,0 40,0 50,0
Acceleration
az[m/s
2
]
3D_Structures_Moving_2014 (Theoretical) 0,1947 0,2328 0,2616
Experimental 0,1746 0,2063 0,2971
Different [%] 11,51 12,85 13,55
(a) Vehicle
15
a) Vehicle b) Result on the screen (01 time)
Fig.17. Experimental procedure
Dynamic measurement system SDA-810C (Japan), made in 2010, with: 8 channels, linear
frequency response: 10kHz, electronic source: DC10.5-30V 1.4A; AC170-250V 50/60Hz
25VA, accuracy: 0,0025%, resolution ADC: 16 bit, sampling rate: 19,2kHz. This equipment
gathers in-situ data that are stored into a computer.
Consider three velocity level of vehicle 30km/h, 40km/h, 50km/h, surcharge 15 times for
each velocity level (n = 15).
4.2. Experimental results
The comparison of results between theoretical calculation by 3D_Structures_Moving_2014
program and experimental method (with three velocity levels) is presented in Fig. 18 and table 3.
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
Time t[s]
A
c
c
e
le
ra
ti
o
n
a
z
[m
/s
2
]
Experimental
Theoretical
Fig. 18. Vertical acceleration responses of considered point (V = 50km/h)
Table 3. Maxi um acceleration of considered point
Car velocity V[km/h] 30,0 40,0 50,0
Acceleration
az[m/s
2
]
3D_Structures_Moving_2014 (Theoretical) 0,1947 0,2 28 0,2616
Experimental 0,1746 0,2063 0,2971
Different [%] 11,51 12,85 13,55
(b) Result on the screen (01 ti e)
Fig. 18. Experimental procedure
4.2. Experimental results
The comparison of re ults between theo etical calculation by 3D Structures Mov-
ing 2014 program and experimental work (wit three velocity levels) is present d in
Fig. 19 and Tab. 3.
Table 3. Maximum acceleration of considered point
Car velocity V [km/h] 30.0 40.0 50.0
Acceleration 3D Structures Moving 2014 (Theoretical) 0.1947 0.2328 0.2616
az[m/s2] Experimental 0.1746 0.2063 0.2971
Different [%] 11.51 12.85 13.55
It is obtained that the dynamic responses measured at the considered points are
more uneven than those by theoretical calculation. The maximum differences of vertical
Dynamic response of three dimension tunnel on elastic foundation subjected to moving vehicle loads 121
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
-0.4
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0.4
Time t[s]
A
c
c
e
le
ra
tio
n
a
z
[m
/s
2
]
Experimental
Theoretical
Fig. 19. Vertical acceleration responses at considered point (V = 50 km/h)
acceleration with three velocity levels are from 11.51% to 13.55%. This result shows that
experimental results agree with calculation results. Therefore, we realize that
3D Structures Moving 2014 calculation program is reliable.
5. CONCLUSION
This paper presented an algorithm of element finite method established for dy-
namic analysis of tunnel and foundation in space model subjected to moving loads of
vehicle. Numerical investigation has been carried out for an example with different pa-
rameters and showed effects of parameters of structure and load to the dynamic response
of tunnel-foundation system. The established finite element model and the computer
program were tested on a real tunnel. The obtained experimental results are acceptably
agreed with the numerical ones.
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