Kiến trúc xây dựng - Chương 9: Mechanics of materials
          
        
            
            
              
            
 
            
                
                    Principle of Superposition:
• Deformations of beams subjected to
combinations of loadings may be
obtained as the linear combination of
the deformations from the individual
loadings
                
              
                                            
                                
            
 
            
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MECHANICS OF 
MATERIALS
Third Edition
Ferdinand P. Beer
E. Russell Johnston, Jr.
John T. DeWolf
Lecture Notes:
J. Walt Oler
Texas Tech University
CHAPTER
© 2002 The McGraw-Hill Companies, Inc. All rights reserved.
Deflection of Beams
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 2
Deflection of Beams
Deformation of a Beam Under Transverse 
Loading
Equation of the Elastic Curve
Direct Determination of the Elastic Curve 
From the Load Di...
Statically Indeterminate Beams
Sample Problem 9.1
Sample Problem 9.3
Method of Superposition
Sample Problem 9.7
Application of Superposition to Statically 
Indeterminate ...
Sample Problem 9.8
Moment-Area Theorems
Application to Cantilever Beams and 
Beams With Symmetric ...
Bending Moment Diagrams by Parts
Sample Problem 9.11
Application of Moment-Area Theorems to 
Beams With Unsymme...
Maximum Deflection
Use of Moment-Area Theorems With 
Statically Indeterminate...
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 3
Deformation of a Beam Under Transverse Loading
• Relationship between bending moment and 
curvature for pure bending remains valid for 
general transverse loadings.
EI
xM )(1 =ρ
• Cantilever beam subjected to concentrated 
load at the free end,
EI
Px−=ρ
1
• Curvature varies linearly with x
• At the free end A, ∞== A
A
 ρ
ρ
,01
• At the support B, PL
EI
B
B
=≠ ρρ ,0
1
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 4
Deformation of a Beam Under Transverse Loading
• Overhanging beam
• Reactions at A and C
• Bending moment diagram
• Curvature is zero at points where the bending 
moment is zero, i.e., at each end and at E.
EI
xM )(1 =ρ
• Beam is concave upwards where the bending 
moment is positive and concave downwards 
where it is negative.
• Maximum curvature occurs where the moment 
magnitude is a maximum.
• An equation for the beam shape or elastic curve
is required to determine maximum deflection 
and slope.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 5
Equation of the Elastic Curve
• From elementary calculus, simplified for beam 
parameters,
2
2
232
2
2
1
1
dx
yd
dx
dy
dx
yd
≈
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛+
=ρ
• Substituting and integrating,
( )
( )
( ) 21
00
1
0
2
21
CxCdxxMdxyEI
CdxxM
dx
dyEIEI
xM
dx
ydEIEI
xx
x
++=
+=≈
==
∫∫
∫θ
ρ
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 6
Equation of the Elastic Curve
( ) 21
00
CxCdxxMdxyEI
xx
++= ∫∫
• Constants are determined from boundary 
conditions
• Three cases for statically determinant beams,
– Simply supported beam
0,0 == BA yy
– Overhanging beam
0,0 == BA yy
– Cantilever beam
0,0 == AAy θ
• More complicated loadings require multiple 
integrals and application of requirement for 
continuity of displacement and slope.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 7
Direct Determination of the Elastic Curve From the 
Load Distribution
• For a beam subjected to a distributed load,
( ) ( )xw
dx
dV
dx
MdxV
dx
dM −=== 2
2
• Equation for beam displacement becomes
( )xw
dx
ydEI
dx
Md −== 4
4
2
2
( ) ( )
43
2
22
13
16
1 CxCxCxC
dxxwdxdxdxxyEI
++++
−= ∫∫∫∫
• Integrating four times yields
• Constants are determined from boundary 
conditions.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 8
Statically Indeterminate Beams
• Consider beam with fixed support at A and roller 
support at B.
• From free-body diagram, note that there are four 
unknown reaction components.
• Conditions for static equilibrium yield
000 =∑=∑=∑ Ayx MFF
The beam is statically indeterminate.
( ) 21
00
CxCdxxMdxyEI
xx
++= ∫∫
• Also have the beam deflection equation,
which introduces two unknowns but provides 
three additional equations from the boundary 
conditions:
0,At 00,0At ===== yLxyx θ
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 9
Sample Problem 9.1
ft 4ft15kips50
psi1029in7236814 64
===
×==×
aLP
EIW
For portion AB of the overhanging beam, 
(a) derive the equation for the elastic curve, 
(b) determine the maximum deflection, 
(c) evaluate ymax.
SOLUTION:
• Develop an expression for M(x) 
and derive differential equation for 
elastic curve.
• Integrate differential equation twice 
and apply boundary conditions to 
obtain elastic curve.
• Locate point of zero slope or point 
of maximum deflection.
• Evaluate corresponding maximum 
deflection.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 10
Sample Problem 9.1
SOLUTION:
• Develop an expression for M(x) and derive 
differential equation for elastic curve.
- Reactions:
↑⎟⎠
⎞⎜⎝
⎛ +=↓=
L
aPR
L
PaR BA 1
- From the free-body diagram for section AD,
( )Lxx
L
aPM <<−= 0
x
L
aP
dx
ydEI −=2
2
- The differential equation for the elastic 
curve,
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 11
Sample Problem 9.1
PaLCLCL
L
aPyLx
Cyx
6
1
6
10:0,at 
0:0,0at 
11
3
2
=+−===
===
• Integrate differential equation twice and apply 
boundary conditions to obtain elastic curve.
21
3
1
2
6
1
2
1
CxCx
L
aPyEI
Cx
L
aP
dx
dyEI
++−=
+−=
x
L
aP
dx
ydEI −=2
2
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛−=
32
6 L
x
L
x
EI
PaLy
PaLxx
L
aPyEI
L
x
EI
PaL
dx
dyPaLx
L
aP
dx
dyEI
6
1
6
1
31
66
1
2
1
3
2
2
+−=
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛−=+−=
Substituting,
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 12
Sample Problem 9.1
• Locate point of zero slope or point 
of maximum deflection.
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛−=
32
6 L
x
L
x
EI
PaLy
LLx
L
x
EI
PaL
dx
dy
m
m 577.0
3
31
6
0
2
==
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛−==
• Evaluate corresponding maximum 
deflection.
( )[ ]32max 577.0577.06 −= EIPaLy
EI
PaLy
6
0642.0
2
max =
( )( )( )( )( )46
2
max
in723psi10296
in180in48kips500642.0 ×=y
in238.0max =y
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 13
Sample Problem 9.3
For the uniform beam, determine the 
reaction at A, derive the equation for 
the elastic curve, and determine the 
slope at A. (Note that the beam is 
statically indeterminate to the first 
degree)
SOLUTION:
• Develop the differential equation for 
the elastic curve (will be functionally 
dependent on the reaction at A).
• Integrate twice and apply boundary 
conditions to solve for reaction at A
and to obtain the elastic curve.
• Evaluate the slope at A.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 14
Sample Problem 9.3
• Consider moment acting at section D,
L
xwxRM
Mx
L
xwxR
M
A
A
D
6
0
32
1
0
3
0
2
0
−=
=−⎟⎟⎠
⎞
⎜⎜⎝
⎛−
=∑
L
xwxRM
dx
ydEI A 6
3
0
2
2
−==
• The differential equation for the elastic 
curve,
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 15
Sample Problem 9.3
L
xwxRM
dx
ydEI A 6
3
0
2
2
−==
• Integrate twice
21
5
03
1
4
02
1206
1
242
1
CxC
L
xwxRyEI
C
L
xwxREI
dx
dyEI
A
A
++−=
+−== θ
• Apply boundary conditions:
0
1206
1:0,at 
0
242
1:0,at 
0:0,0at 
21
4
03
1
3
02
2
=++−==
=+−==
===
CLCLwLRyLx
CLwLRLx
Cyx
A
Aθ
• Solve for reaction at A
0
30
1
3
1 4
0
3 =− LwLRA ↑= LwRA 010
1
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 16
Sample Problem 9.3
xLw
L
xwxLwyEI ⎟⎠
⎞⎜⎝
⎛−−⎟⎠
⎞⎜⎝
⎛= 30
5
03
0 120
1
12010
1
6
1
( )xLxLx
EIL
wy 43250 2
120
−+−=
• Substitute for C1, C2, and RA in the 
elastic curve equation,
( )42240 65
120
LxLx
EIL
w
dx
dy −+−==θ
EI
Lw
A 120
3
0=θ
• Differentiate once to find the slope,
at x = 0,
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 17
Method of Superposition
Principle of Superposition:
• Deformations of beams subjected to 
combinations of loadings may be 
obtained as the linear combination of 
the deformations from the individual 
loadings
• Procedure is facilitated by tables of 
solutions for common types of 
loadings and supports.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 18
Sample Problem 9.7
For the beam and loading shown, 
determine the slope and deflection at 
point B.
SOLUTION:
Superpose the deformations due to Loading I and Loading II as shown.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 19
Sample Problem 9.7
Loading I
( )
EI
wL
IB 6
3
−=θ ( )
EI
wLy IB 8
4
−=
Loading II
( )
EI
wL
IIC 48
3
=θ ( )
EI
wLy IIC 128
4
=
In beam segment CB, the bending moment is 
zero and the elastic curve is a straight line.
( ) ( )
EI
wL
IICIIB 48
3
== θθ
( )
EI
wLL
EI
wL
EI
wLy IIB 384
7
248128
434
=⎟⎠
⎞⎜⎝
⎛+=
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 20
Sample Problem 9.7
Combine the two solutions,
EI
wL
B 48
7 3=θ( ) ( )
EI
wL
EI
wL
IIBIBB 486
33
+−=+= θθθ
EI
wLyB 384
41 4=( ) ( )
EI
wL
EI
wLyyy IIBIBB 384
7
8
44
+−=+=
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 21
Application of Superposition to Statically 
Indeterminate Beams
• Method of superposition may be 
applied to determine the reactions at 
the supports of statically indeterminate 
beams.
• Designate one of the reactions as 
redundant and eliminate or modify 
the support.
• Determine the beam deformation 
without the redundant support.
• Treat the redundant reaction as an 
unknown load which, together with 
the other loads, must produce 
deformations compatible with the 
original supports.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 22
Sample Problem 9.8
For the uniform beam and loading shown, 
determine the reaction at each support and 
the slope at end A.
SOLUTION:
• Release the “redundant” support at B, and find deformation.
• Apply reaction at B as an unknown load to force zero displacement at B.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 23
Sample Problem 9.8
• Distributed Loading:
( )
EI
wL
LLLLL
EI
wy wB
4
3
34
01132.0
3
2
3
22
3
2
24
−=
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛+⎟⎠
⎞⎜⎝
⎛−⎟⎠
⎞⎜⎝
⎛−=
• Redundant Reaction Loading:
( )
EI
LRLL
EIL
Ry BBRB
322
01646.0
33
2
3
=⎟⎠
⎞⎜⎝
⎛⎟⎠
⎞⎜⎝
⎛=
• For compatibility with original supports, yB = 0
( ) ( )
EI
LR
EI
wLyy BRBwB
34
01646.001132.00 +−=+=
↑= wLRB 688.0
• From statics,
↑=↑= wLRwLR CA 0413.0271.0
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 24
Sample Problem 9.8
Slope at end A,
( )
EI
wL
EI
wL
wA
33
04167.0
24
−=−=θ
( )
EI
wLLLL
EIL
wL
RA
32
2 03398.0
336
0688.0 =
⎥⎥⎦
⎤
⎢⎢⎣
⎡
⎟⎠
⎞⎜⎝
⎛−⎟⎠
⎞⎜⎝
⎛=θ
EI
wL
A
3
00769.0−=θ( ) ( )
EI
wL
EI
wL
RAwAA
33
03398.004167.0 +−=+= θθθ
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 25
Moment-Area Theorems
• Geometric properties of the elastic curve can 
be used to determine deflection and slope.
• Consider a beam subjected to arbitrary loading,
• First Moment-Area Theorem:
area under (M/EI) diagram between
C and D.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 26
Moment-Area Theorems
• Second Moment-Area Theorem:
The tangential deviation of C with respect to D
is equal to the first moment with respect to a 
vertical axis through C of the area under the 
(M/EI) diagram between C and D.
• Tangents to the elastic curve at P and P’ intercept 
a segment of length dt on the vertical through C.
= tangential deviation of C
with respect to D
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 27
Application to Cantilever Beams and Beams With 
Symmetric Loadings
• Cantilever beam - Select tangent at A as the 
reference. 
• Simply supported, symmetrically loaded 
beam - select tangent at C as the reference.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 28
Bending Moment Diagrams by Parts
• Determination of the change of slope and the 
tangential deviation is simplified if the effect of 
each load is evaluated separately.
• Construct a separate (M/EI) diagram for each 
load. 
- The change of slope, θD/C, is obtained by 
adding the areas under the diagrams.
- The tangential deviation, tD/C is obtained by 
adding the first moments of the areas with 
respect to a vertical axis through D.
• Bending moment diagram constructed from 
individual loads is said to be drawn by parts.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 29
Sample Problem 9.11
For the prismatic beam shown, determine 
the slope and deflection at E.
SOLUTION:
• Determine the reactions at supports.
• Construct shear, bending moment and 
(M/EI) diagrams.
• Taking the tangent at C as the 
reference, evaluate the slope and 
tangential deviations at E.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 30
Sample Problem 9.11
SOLUTION:
• Determine the reactions at supports.
waRR DB ==
• Construct shear, bending moment and 
(M/EI) diagrams.
( )
EI
waa
EI
waA
EI
LwaL
EI
waA
623
1
422
32
2
22
1
−=⎟⎟⎠
⎞
⎜⎜⎝
⎛−=
−=⎟⎠
⎞⎜⎝
⎛−=
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 31
Sample Problem 9.11
• Slope at E:
EI
wa
EI
LwaAA
CECECE
64
32
21 −−=+=
=+= θθθθ
( )aL
EI
wa
E 2312
2
+−=θ
⎥⎥⎦
⎤
⎢⎢⎣
⎡−−
⎥⎥⎦
⎤
⎢⎢⎣
⎡ −−−=
⎥⎦
⎤⎢⎣
⎡ ⎟⎠
⎞⎜⎝
⎛−⎥⎦
⎤⎢⎣
⎡ ⎟⎠
⎞⎜⎝
⎛+⎟⎠
⎞⎜⎝
⎛ +=
−=
EI
Lwa
EI
wa
EI
Lwa
EI
Lwa
LAaALaA
tty CDCEE
168164
44
3
4
224223
121
( )aL
EI
wayE +−= 28
3
• Deflection at E:
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 32
Application of Moment-Area Theorems to Beams 
With Unsymmetric Loadings
• Define reference tangent at support A. Evaluate θA
by determining the tangential deviation at B with 
respect to A.
• The slope at other points is found with respect to 
reference tangent.
ADAD θθθ +=
• The deflection at D is found from the tangential 
deviation at D.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 33
Maximum Deflection
• Maximum deflection occurs at point K
where the tangent is horizontal.
• Point K may be determined by measuring 
an area under the (M/EI) diagram equal 
to -θA .
• Obtain ymax by computing the first 
moment with respect to the vertical axis 
through A of the area between A and K.
© 2002 The McGraw-Hill Companies, Inc. All rights reserved. 
MECHANICS OF MATERIALS
Third
Edition
Beer • Johnston • DeWolf
9 - 34
Use of Moment-Area Theorems With Statically 
Indeterminate Beams
• Reactions at supports of statically indeterminate 
beams are found by designating a redundant 
constraint and treating it as an unknown load which 
satisfies a displacement compatibility requirement.
• The (M/EI) diagram is drawn by parts. The 
resulting tangential deviations are superposed and 
related by the compatibility requirement.
• With reactions determined, the slope and deflection 
are found from the moment-area method.
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